IT प्रवेश – B.Sc. CSIT, BIT, BCA
IT प्रवेश – B.Sc. CSIT, BIT, BCA
IT Entrance – B.Sc. CSIT, BIT & BCA · २,५९२ प्रश्न
२,५९२ प्रश्न उपलब्ध। मोड छान्नुहोस्:
IT प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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The terminal velocity of a small spherical body falling through a viscous fluid is proportional to (r = radius):
सही उत्तर: ग) r²
From Stokes' law, v_t = 2r²(ρ − σ)g/(9η), so v_t ∝ r². Doubling the radius makes the terminal velocity four times larger.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The height to which a liquid rises in a capillary tube is:
सही उत्तर: ख) Inversely proportional to the radius of the tube
From Jurin's law h = 2T cosθ/(rρg), so h ∝ 1/r. That is why a liquid rises higher in a narrower tube.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The SI unit of surface tension is:
सही उत्तर: क) N/m
Surface tension is force per unit length, so its unit is N/m (equivalently J/m²). N/m² is the unit of pressure and N·s/m² is the unit of viscosity.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Hooke's law, stress ∝ strain, is valid only:
सही उत्तर: ग) Within the elastic limit
Hooke's law holds up to the proportional (elastic) limit; beyond it the material may deform permanently. The constant of proportionality is the modulus of elasticity.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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According to Kepler's third law, the time period T of a planet and the semi-major axis r of its orbit are related as:
सही उत्तर: ख) T² ∝ r³
Kepler's law of periods states T² ∝ r³. For example, a planet four times farther from the Sun has a period eight times longer.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The value of acceleration due to gravity at the centre of the Earth is:
सही उत्तर: क) Zero
Inside a uniform Earth g' = g(1 − d/R); at the centre d = R, so g' = 0. Gravity is maximum at the surface, not at the centre.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Near the Earth's surface, the ratio of escape velocity to orbital velocity is:
सही उत्तर: ख) √2
v_e = √(2gR) and v_o = √(gR), so v_e/v_o = √2. This is why 11.2 km/s ≈ 1.414 × 7.9 km/s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The acceleration due to gravity at a height equal to the radius of the Earth (h = R) above the surface is:
सही उत्तर: घ) g/4
g' = g R²/(R + h)² = g R²/(2R)² = g/4. The value g/9 would apply at a height of 2R.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Torque has the same dimensions as:
सही उत्तर: ग) Work
Torque = force × perpendicular distance, giving [ML²T⁻²], the same as work or energy. However, torque is a vector and is written in N·m, not in joules.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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When a spinning ice skater pulls her arms inward, her angular velocity:
सही उत्तर: ख) Increases
With no external torque, angular momentum L = Iω is conserved. Pulling arms in decreases the moment of inertia I, so ω increases.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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