CTEVT डिप्लोमा इन्जिनियरिङ डिप्लोमा इन सिभिल/कम्प्युटर/इलेक्ट्रिकल प्रवेश तयारी
CTEVT डिप्लोमा इन्जिनियरिङ – डिप्लोमा इन सिभिल/कम्प्युटर/इलेक्ट्रिकल प्रवेश
CTEVT Diploma Entrance · CTEVT Diploma in Engineering
१,५७१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
CTEVT डिप्लोमा इन्जिनियरिङ प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A 1000 W heater is used for 3 hours daily for 30 days. If electricity costs Rs 10 per unit, the cost is:
सही उत्तर: घ) Rs 900
Energy = 1 kW × 3 h × 30 = 90 kWh (units); cost = 90 × 10 = Rs 900. Rs 90 is the number of units, not the cost.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A bulb draws 0.5 A when connected to a 220 V supply. Its power is:
सही उत्तर: ख) 110 W
P = VI = 220 × 0.5 = 110 W. 440 comes from dividing 220 by 0.5.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Two 6 Ω resistors are connected in parallel. The equivalent resistance is:
सही उत्तर: क) 3 Ω
1/R = 1/6 + 1/6 = 1/3, so R = 3 Ω. For n equal resistors in parallel, R = R/n; 12 Ω would be the series value.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Resistors of 2 Ω, 3 Ω and 5 Ω are connected in series. The equivalent resistance is:
सही उत्तर: ग) 10 Ω
In series, R = R₁ + R₂ + R₃ = 2 + 3 + 5 = 10 Ω. About 0.97 Ω would be the parallel combination.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 12 V battery is connected across a 4 Ω resistor. The current through it is:
सही उत्तर: घ) 3 A
By Ohm's law I = V/R = 12/4 = 3 A. 48 comes from wrongly multiplying V and R.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A student can read a book clearly but cannot see the writing on a distant blackboard. The defect and its correcting lens are:
सही उत्तर: ख) Myopia, concave lens
Not seeing far objects clearly is myopia (short-sightedness), corrected with a diverging concave lens. Hypermetropia is the opposite defect, corrected with a convex lens.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A concave mirror has a radius of curvature of 30 cm. Its focal length is:
सही उत्तर: घ) 15 cm
For a spherical mirror f = R/2 = 30/2 = 15 cm. 60 cm comes from wrongly doubling R.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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An object placed 20 cm from a convex lens forms a real image 60 cm from the lens. The magnitude of magnification is:
सही उत्तर: घ) 3
Magnification m = v/u = 60/20 = 3, so the image is three times the size of the object. 1/3 results from inverting the ratio.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The power of a convex lens of focal length 25 cm is:
सही उत्तर: ख) +4 D
P = 1/f (in metres) = 1/0.25 = +4 D. The sign is positive for a convex (converging) lens; −4 D would be a concave lens.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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An object is placed 15 cm in front of a convex lens of focal length 10 cm. The image is formed at:
सही उत्तर: ख) 30 cm on the other side of the lens
Using 1/v − 1/u = 1/f with u = −15 cm: 1/v = 1/10 − 1/15 = 1/30, so v = +30 cm (real image). An object between F and 2F gives a real image beyond 2F.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।