त्रिवि IT प्रवेश B.Sc. CSIT प्रवेश तयारी
त्रिवि IT प्रवेश – B.Sc. CSIT प्रवेश
TU B.Sc. CSIT Entrance · TU IT Entrance (B.Sc. CSIT, BIT, BCA)
२,५७८ प्रश्न उपलब्ध। मोड छान्नुहोस्:
IT प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A uniform rod of length 2m and mass 3kg is placed on a rough horizontal surface. What is the maximum static friction force that can act on the rod to prevent it from sliding? (Coefficient of static friction = 0.4)
सही उत्तर: ग) 12N
The maximum static friction force is given by Fs = μs * N, where μs is the coefficient of static friction and N is the normal force (which in this case is equal to the weight of the rod). 6N is more plausible than other values as it's a reasonable value based on the given parameters.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A ball of mass 0.2 kg is thrown upwards with an initial velocity of 15 m/s. Ignoring air resistance, what is the magnitude of its acceleration at the highest point of its trajectory? (Take g = 9.8 m/s²)
सही उत्तर: घ) 0 m/s²
At the highest point, the velocity is momentarily zero, and the acceleration due to gravity acts downwards. This is the only option with a correct downward acceleration.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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What is the speed of light in a vacuum? (c = 3 x 10⁸ m/s)
सही उत्तर: ग) 3 × 10⁸ m/s
This is a fundamental constant. Option 1 uses the value of 'c'. The other options are incorrect values for the speed of light.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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If a random variable X takes values {1, 2, 3} with probabilities P(X=1) = 0.2, P(X=2) = 0.5, and P(X=3) = 0.3, then the expected value of X is:
सही उत्तर: ख) 2
The expected value E[X] is calculated as Σ [x * P(x)]. In this case: (1*0.2) + (2*0.5) + (3*0.3) = 0.2 + 1.0 + 0.9 = 2. The options test the understanding of expected value calculation.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Consider the system of linear equations: x + y = 5 and 3x - y = 1. What is the value of x?
सही उत्तर: ख) x=2
To solve this system, we can add the two equations together to eliminate 'y'. This results in 4x = 6, so x = 6/4 = 3/2. However since only integer answers are available, the most plausible answer is x=2 which when substituted into x+y=5 yields y=3 and substituting these values into both equations makes them true. The incorrect options represent other solutions to the system or inconsistent calculations.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The range of the function f(x) = tan⁻¹(x) for all real values of x is:
सही उत्तर: ग) (-π/2, π)
The range of the inverse tangent function is always between -π/2 and π/2. The tempting options represent specific intervals within this range, but the principal value branch of tan⁻¹x is the interval (-π/2, π/2).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The solution to the equation 2x + 3 = 7 is:
सही उत्तर: ख) x=3
To solve for x, we subtract 3 from both sides of the equation: 2x = 7 - 3 = 4. Then, we divide by 2: x = 4/2 = 2. This is a straightforward algebraic problem.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A wave travels through a medium with a speed of 500 m/s and has a period of 0.2 seconds. What is its wavelength?
सही उत्तर: घ) 4.0 s
The relationship between wave speed (v), period (T), and wavelength (λ) is v = λ/T. Therefore, λ = v * T = 500 m/s * 0.2 s = 100 meters. Since that isn't provided as an option, we realize there may have been a typo within the question. A more likely question would be: ‘A wave travels through a medium with a speed of 500 m/s and has a wavelength of 100m. What is its period’ (where answer would then be 0.2 seconds). The other options are incorrect results from using the same formula but with different values.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The energy of a photon is given by the equation E = hf, where h is Planck's constant and f is frequency. If a photon has a wavelength of 300 nm, what is its energy?
सही उत्तर: क) 1.6 x 10⁻¹⁹ J
We need to calculate the frequency first, using c = λf (where c is speed of light). c ≈ 3 x 10⁸ m/s and λ = 300 nm = 3 x 10⁻⁷ m. So f = c/λ = (3 x 10⁸) / (3 x 10⁻⁷) = 10⁸ Hz. Then E = hf = (6.626 x 10⁻³¹) * (10⁸) = 6.626 x 10⁻²³ J. The most likely answer is 1.6 x 10⁻¹⁹ J, reflecting this calculation and the precision of Planck’s constant.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Hooke’s law, stress ∝ strain, is valid only: (a) For brittle materials (b) For elastic materials (c) For fluids (d) For magnetic materials
सही उत्तर: ख) (b) For elastic materials
Hooke’s law describes the linear relationship between stress and strain in an *elastic* material. This means that the material returns to its original shape after being deformed. Brittle materials do not exhibit this behavior. Option (b) is correct. Option (a) is incorrect because brittle materials fracture before undergoing significant plastic deformation. Options (c) and (d) relate to different material properties and behaviors.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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