Quantitative (गणित) – Quantitative Ability MCQ
Quantitative (गणित) – व्यवस्थापन प्रवेश
Quantitative Ability · Management Entrance – English, Quant, Logical Reasoning & GK · १,३१७ प्रश्न
१,३१७ प्रश्न उपलब्ध। मोड छान्नुहोस्:
Quantitative (गणित): प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A and B can do a work in 10 days, B and C in 15 days, and C and A in 12 days. In how many days can A, B and C together do it?
सही उत्तर: ख) 8 days
2(A + B + C) = 1/10 + 1/15 + 1/12 = 1/4, so A + B + C = 1/8 per day, i.e. 8 days.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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8 men working 6 hours a day can finish a job in 15 days. In how many days will 10 men working 8 hours a day finish it?
सही उत्तर: ग) 9 days
Man-hours = 8 x 6 x 15 = 720; days = 720 / (10 x 8) = 9 days.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A and B together can finish a work in 12 days, and A alone can finish it in 20 days. In how many days can B alone finish it?
सही उत्तर: ख) 30 days
B's one-day work = 1/12 - 1/20 = 2/60 = 1/30, so B alone takes 30 days.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A can do 1/3 of a work in 5 days and B can do 2/5 of it in 10 days. In how many days can they finish the whole work together?
सही उत्तर: क) 9 3/8 days
A alone = 15 days, B alone = 25 days; together 1/15 + 1/25 = 8/75 per day, so time = 75/8 = 9 3/8 days.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The present ages of a father and his son are in the ratio 7 : 2. After 10 years the ratio will be 9 : 4. What is the son's present age?
सही उत्तर: घ) 10 years
(7k + 10)/(2k + 10) = 9/4 gives 28k + 40 = 18k + 90, so k = 5 and the son is 2 x 5 = 10 years.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A is 5 years older than B. Five years ago, A was twice as old as B. What is B's present age?
सही उत्तर: घ) 10 years
A = B + 5 and B = 2(B - 5) (since A - 5 = B), giving B = 10 years.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Ten years ago, A was half as old as B. If their present ages are in the ratio 3 : 4, what is the sum of their present ages?
सही उत्तर: ख) 35 years
Let ages be 3k and 4k: 3k - 10 = (4k - 10)/2 gives k = 5, so ages are 15 and 20, sum 35 years.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The sum of the present ages of A and B is 60 years and their ages are in the ratio 7 : 5. What is B's age?
सही उत्तर: घ) 25 years
B = 60 x 5/12 = 25 years (A = 35 years).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The average of 11 results is 50. The average of the first six is 49 and that of the last six is 52. What is the sixth result?
सही उत्तर: क) 56
Sixth result = (6 x 49 + 6 x 52) - 11 x 50 = 294 + 312 - 550 = 56.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The average marks of 40 students are 52. If the 25 boys have an average of 55, what is the average of the girls?
सही उत्तर: ग) 47
Total = 40 x 52 = 2,080; boys = 25 x 55 = 1,375; girls' total = 705 for 15 girls, average = 47.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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