नेपाल व्यावसायिक लाइसेन्स नेपाल बार काउन्सिल अधिवक्ता परीक्षा तयारी
नेपाल व्यावसायिक लाइसेन्स – नेपाल बार काउन्सिल अधिवक्ता परीक्षा
Advocate License Exam · Nepal Professional License Exams
२,४१४ प्रश्न उपलब्ध। मोड छान्नुहोस्:
लाइसेन्स परीक्षा: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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For Fe 500 grade reinforcement, the limiting depth of neutral axis ratio xu,max/d in limit state design to IS 456 is:
सही उत्तर: ख) 0.46
IS 456 gives xu,max/d = 0.53 for Fe 250, 0.48 for Fe 415 and 0.46 for Fe 500.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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An activity has a normal duration of 10 days at Rs 20,000 and a crash duration of 6 days at Rs 28,000. Its cost slope is:
सही उत्तर: ग) Rs 2,000 per day
Cost slope = (crash cost − normal cost)/(normal time − crash time) = (28,000 − 20,000)/(10 − 6) = Rs 2,000 per day.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In CPM, the interfering float of an activity is equal to its:
सही उत्तर: ग) Total float minus free float
Interfering float = total float − free float; it is the part of the float whose use delays the start of following activities.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A simply supported beam of span L has plastic moment capacity Mp. The collapse load for a single point load at mid-span is:
सही उत्तर: घ) 4Mp/L
Collapse occurs when the mid-span moment WL/4 reaches Mp, so Wc = 4Mp/L.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The plastic section modulus of a rectangular section of width b and depth d about its major axis is:
सही उत्तर: क) bd²/4
Zp = 2 × (b·d/2) × d/4 = bd²/4; bd²/6 is the elastic section modulus.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The shape factor of a solid circular cross-section in plastic analysis is about:
सही उत्तर: ख) 1.70
Shape factor = Zp/Ze = (d³/6)/(πd³/32) = 16/(3π) ≈ 1.70 for a solid circle; 1.5 is for a rectangle and about 1.14 for I-sections.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The degree of static indeterminacy of a rigid-jointed plane frame having m members, r external reaction components and j joints is:
सही उत्तर: ख) 3m + r − 3j
Each member of a rigid plane frame has 3 unknown internal forces and each joint gives 3 equilibrium equations, so Ds = 3m + r − 3j.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In the unit load (virtual work) method, the deflection at a point of a beam due to bending is obtained from:
सही उत्तर: ग) ∫ M m dx / (EI)
Deflection δ = ∫ M m dx/EI, where M is the moment due to actual loads and m the moment due to a unit load at the point in the direction of δ.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The influence line diagram for the reaction at one support of a simply supported beam is:
सही उत्तर: घ) A triangle with ordinate 1 at that support, reducing to zero at the other support
As a unit load moves from that support to the other, the reaction falls linearly from 1 to 0, giving a triangular influence line.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A single concentrated load W rolls across a simply supported beam of span L. The absolute maximum bending moment in the beam is:
सही उत्तर: क) WL/4, when the load is at mid-span
The bending moment under a point load at distance x is Wx(L − x)/L, which is maximum (WL/4) when x = L/2.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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