सिभिल इन्जिनियरिङ
सिभिल इन्जिनियरिङ
Civil Engineering · ५,१७१ प्रश्न
५,१७१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
सिभिल इन्जिनियरिङ: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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The rate of change of bending moment along a beam (dM/dx) is equal to the:
सही उत्तर: क) Shear force
From the equilibrium of a beam element, dM/dx = V (shear force) and dV/dx = −w (load intensity).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a cantilever carrying only a uniformly distributed load over its whole length, the shear force diagram is:
सही उत्तर: ग) A sloping straight line (triangle), maximum at the fixed end
Shear at distance x from the free end is wx, which varies linearly from zero at the free end to wL at the fixed end.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A simply supported beam of span L carries a triangular load whose intensity increases uniformly from zero at one end to a maximum at the other, with total load W. The maximum bending moment is:
सही उत्तर: क) WL/(9√3) ≈ 0.064WL
For a triangular load the maximum moment occurs at L/√3 from the zero-load end and equals WL/(9√3) ≈ 0.064WL.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A beam has an overhang of 2 m beyond its right support with a point load of 30 kN at the free end of the overhang. The hogging bending moment at that support is:
सही उत्तर: घ) 60 kN·m
Taking moments of the forces on the overhang about the support: M = 30 × 2 = 60 kN·m (hogging).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A cantilever 4 m long carries a point load of 10 kN at a distance of 2 m from the fixed end. The bending moment at the fixed end is:
सही उत्तर: क) 20 kN·m
Moment at the fixed end = load × its lever arm from the support = 10 × 2 = 20 kN·m; the part beyond the load carries no moment.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A simply supported beam of 8 m span carries a UDL of 10 kN/m over the whole span and a point load of 20 kN at midspan. The maximum bending moment is:
सही उत्तर: क) 120 kN·m
Both maxima occur at midspan, so M = wL²/8 + WL/4 = 10 × 64/8 + 20 × 8/4 = 80 + 40 = 120 kN·m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A simply supported beam of 6 m span carries a point load of 60 kN at 2 m from one support. The maximum bending moment is:
सही उत्तर: क) 80 kN·m
Mmax = W·a·b/L = 60 × 2 × 4/6 = 80 kN·m, occurring under the load.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A simply supported beam of 6 m span carries a point load of 60 kN at 2 m from the left support A. The reaction at A is:
सही उत्तर: ग) 40 kN
RA = W·b/L = 60 × 4/6 = 40 kN (the support nearer the load takes the larger share).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Nepal, which extends from about 80° E to 88° E longitude, falls in which UTM zones?
सही उत्तर: ख) Zones 44 and 45
Zone 44 covers 78°–84° E and zone 45 covers 84°–90° E, so Nepal lies in zones 44 and 45.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Since each UTM zone is 6° wide in longitude, the total number of UTM zones around the world is:
सही उत्तर: क) 60
360° ÷ 6° = 60 zones, numbered eastward from 180° longitude.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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