संरचना विश्लेषण र RCC – Structures & RCC MCQ
संरचना विश्लेषण र RCC – सिभिल इन्जिनियरिङ
Structures & RCC · Civil Engineering · ५०१ प्रश्न
५०१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
संरचना विश्लेषण र RCC: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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In a three-hinged parabolic arch carrying a UDL over its entire span, the bending moment at every section is:
सही उत्तर: घ) Zero
The parabolic shape matches the funicular polygon of a UDL, so the arch is in pure compression and the moment is zero everywhere.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A three-hinged parabolic arch of span 20 m and central rise 4 m carries a UDL of 10 kN/m over the whole span. The horizontal thrust at each support is:
सही उत्तर: क) 125 kN
H = wL²/(8h) = 10 × 20²/(8 × 4) = 125 kN.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a truss, if two non-collinear members meet at an unloaded joint, the forces in those members are:
सही उत्तर: ग) Both zero
Equilibrium in two non-parallel directions at an unloaded joint with only two non-collinear members requires each member force to be zero.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The force method (method of consistent deformation) of analysing indeterminate structures takes as primary unknowns the:
सही उत्तर: घ) Redundant forces
In the force (flexibility) method redundant forces are unknowns and compatibility equations are written; displacement methods use joint displacements as unknowns.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In the approximate portal method for analysing building frames under lateral loads, it is assumed that:
सही उत्तर: घ) Points of contraflexure occur at mid-height of columns and mid-span of beams
The portal method places hinges (contraflexure points) at mid-points of all members and shares storey shear so interior columns take twice that of exterior columns.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Kani's method of structural analysis is essentially:
सही उत्तर: ग) An iterative method based on rotation and sway contributions at joints
Kani's method distributes rotation (and sway) contributions at joints by iteration, a refinement of the slope-deflection approach.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In the moment distribution method, the carry-over factor to a far end that is hinged (pinned) is:
सही उत्तर: ख) 0
A hinged far end cannot resist moment, so nothing is carried over to it (carry-over factor = 0).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The moment required at the near end of a prismatic member (far end fixed) to produce a unit rotation there is:
सही उत्तर: घ) 4EI/L
The rotational stiffness of a prismatic member with far end fixed is 4EI/L; with far end hinged it reduces to 3EI/L.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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At a rigid joint B, member BA (length 4 m) and member BC (length 6 m) are both far-end fixed and have the same EI. The distribution factor for BA is:
सही उत्तर: क) 0.6
Stiffness ∝ 4EI/L: kBA ∝ 1/4, kBC ∝ 1/6; DF(BA) = (1/4)/(1/4 + 1/6) = 0.6.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A single-bay portal frame has both column bases fixed. Its degree of static indeterminacy is:
सही उत्तर: क) 3
Each fixed base gives 3 reactions (total 6) against 3 equilibrium equations, so the frame is indeterminate to degree 6 − 3 = 3.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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