सिभिल इन्जिनियरिङ
सिभिल इन्जिनियरिङ
Civil Engineering · ५,१७१ प्रश्न
५,१७१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
सिभिल इन्जिनियरिङ: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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Using the approximate formula offset = x²/(2R), the perpendicular offset from the tangent at 20 m from the tangent point for a curve of radius 200 m is:
सही उत्तर: ख) 1.0 m
Offset = 20² / (2 × 200) = 400 / 400 = 1.0 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A vertical curve formed where a falling (descending) gradient meets a rising (ascending) gradient is a:
सही उत्तर: ख) Valley (sag) curve
Valley or sag curves occur where the road changes from down-grade to up-grade, forming a low point.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Superelevation (cant) is provided on horizontal curves of roads and railways to:
सही उत्तर: ग) Counteract the effect of centrifugal force on vehicles
Raising the outer edge introduces a component of weight towards the centre, balancing centrifugal force.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The shift of a circular curve due to a transition curve of length L and radius R is approximately L²/(24R). For L = 60 m and R = 300 m, the shift is:
सही उत्तर: घ) 0.5 m
Shift = 60² / (24 × 300) = 3600 / 7200 = 0.5 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A curve consisting of two circular arcs bending in opposite directions, with a common tangent at the junction, is a:
सही उत्तर: ग) Reverse curve
In a reverse (serpentine) curve, the arcs curve in opposite directions; a compound curve bends in the same direction.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The point of intersection of two straights has chainage 1000.0 m and the tangent length of the curve is 109.2 m. The chainage of the point of curvature (beginning of curve) is:
सही उत्तर: ख) 890.8 m
Chainage of PC = chainage of PI − tangent length = 1000.0 − 109.2 = 890.8 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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For a simple circular curve of radius 200 m and deflection angle 60°, the apex distance R(sec Δ/2 − 1) is about:
सही उत्तर: क) 30.9 m
Apex distance = 200 (sec 30° − 1) = 200 (1.1547 − 1) ≈ 30.9 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Trilateration differs from triangulation in that, in trilateration:
सही उत्तर: घ) The lengths of the sides of triangles are measured (e.g. by EDM) instead of mainly angles
With EDM, all sides can be measured directly and angles computed, which is trilateration.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Spherical excess in a spherical triangle amounts to about 1 second for every:
सही उत्तर: क) 196 km² of area
Spherical excess ≈ 1" per 196 km², so it matters only in large geodetic triangles.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In triangulation, the 'phase correction' is applied because:
सही उत्तर: क) One side of a cylindrical signal is illuminated by the sun, so the observer bisects the bright part rather than the centre
Phase is the error of bisecting the apparently brighter portion of a signal; the correction reduces the sight to the signal's centre.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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