इन्जिनियरिङ सेवा असिस्टेन्ट सब-इन्जिनियर (चौथो तह) – प्राविधिक पत्र
इन्जिनियरिङ सेवा – असिस्टेन्ट सब-इन्जिनियर (चौथो तह)
Assistant Sub-Engineer – 4th Level · Engineering Service
१,५०३ प्रश्न उपलब्ध। मोड छान्नुहोस्:
प्राविधिक पत्र: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ५ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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The Beaman stadia arc fitted to some alidades and theodolites is used to:
सही उत्तर: क) Read directly the factors needed for horizontal distance and difference in elevation, avoiding trigonometric computation
The Beaman arc gives H and V scale readings for inclined sights, simplifying stadia reductions.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In the movable hair (subtense) method of tacheometry:
सही उत्तर: घ) The staff intercept is kept fixed between targets and the distance between the hairs is varied with a micrometer screw
The hairs are moved by micrometer screws to bisect fixed targets on the staff, and the distance is found from the micrometer reading.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A tacheometer with K = 100 and C = 0 is sighted at an angle of elevation of 10° to a vertical staff, and the staff intercept is 1.00 m. The vertical component V is about:
सही उत्तर: ग) 17.10 m
V = ½ Ks sin 2θ = ½ × 100 × 1.00 × sin 20° = 50 × 0.3420 ≈ 17.10 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The stadia constants K and C of a tacheometer can be determined in the field by:
सही उत्तर: ख) Observing staff intercepts at two or more accurately measured distances and solving the equations D = Ks + C
Each known distance gives an equation D = Ks + C; two or more such observations give K and C.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Plotting a traverse by computed coordinates is preferred over plotting by protractor and scale because:
सही उत्तर: क) Errors do not accumulate from one station to the next
Each station is plotted independently from its coordinates, whereas plotting angle by angle carries errors forward.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The double meridian distance (DMD) method is used in traverse computations to:
सही उत्तर: घ) Calculate the area enclosed by a closed traverse
Area = ½ Σ (DMD × latitude) for each line, using meridian distances measured from a reference meridian.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A traverse line 80 m long has a whole circle bearing of 300°. Its departure is:
सही उत्तर: ग) −69.28 m
Departure = L sin θ = 80 × sin 300° = 80 × (−0.866) = −69.28 m (the line runs towards the north-west).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A traverse that starts at one point of known position and ends at another point of known position is called a:
सही उत्तर: ख) Link (connecting) traverse
A link traverse joins two known points (e.g. control stations), so its closure can be checked.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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An open traverse is considered less satisfactory than a closed traverse because:
सही उत्तर: क) It provides no check on the accuracy of the field work
Since an open traverse does not return to a known point, errors cannot be detected or adjusted.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a closed traverse, the algebraic sum of the deflection angles (right positive, left negative) should be:
सही उत्तर: घ) 360°
For a closed polygon the deflection angles add up algebraically to one full turn, 360°.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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