इन्जिनियरिङ सेवा असिस्टेन्ट सब-इन्जिनियर (चौथो तह) – प्राविधिक पत्र
इन्जिनियरिङ सेवा – असिस्टेन्ट सब-इन्जिनियर (चौथो तह)
Assistant Sub-Engineer – 4th Level · Engineering Service
१,५०३ प्रश्न उपलब्ध। मोड छान्नुहोस्:
प्राविधिक पत्र: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ५ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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In compass traversing, the 'free needle' method means that:
सही उत्तर: घ) The bearing of each line is observed directly with respect to the magnetic meridian at every station
In the free needle method the needle is free at every station, so magnetic bearings of lines are read independently.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a closed traverse, if the length and bearing of one line could not be measured, they can be computed because:
सही उत्तर: ग) The algebraic sums of latitudes and of departures of a closed traverse must each be zero
Using ΣL = 0 and ΣD = 0, the latitude and departure of the missing line, and hence its length and bearing, can be found.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The latitude and departure of a traverse line, giving the coordinates of its end relative to its start, are called:
सही उत्तर: घ) Consecutive coordinates
Consecutive coordinates refer each point to the preceding point; independent coordinates refer all points to a common origin.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Gale's traverse table is used for:
सही उत्तर: क) Systematically computing latitudes, departures and coordinates of a traverse
Gale's table organises traverse computations: bearings, latitudes, departures, corrections and coordinates.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The coordinates of three stations are A(0, 0), B(40, 0) and C(0, 30) in metres. The area of triangle ABC by the coordinate method is:
सही उत्तर: क) 600 m²
Area = ½ |x1(y2 − y3) + x2(y3 − y1) + x3(y1 − y2)| = ½ |0 + 40 × 30 + 0| = 600 m².
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A traverse line 100 m long has a whole circle bearing of 150°. Its latitude and departure are:
सही उत्तर: ग) −86.60 m and +50.00 m
Latitude = 100 cos 150° = −86.60 m; departure = 100 sin 150° = +50.00 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The measured interior angles of a closed four-sided traverse total 360°02'. If the angles were measured with equal care, the correction to each angle is:
सही उत्तर: ग) −30"
Total error = +2' = 120"; distributed equally among 4 angles gives −30" each.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The sum of the exterior angles of a closed traverse having 5 sides should be:
सही उत्तर: ख) 1260°
Sum of exterior angles = (2n + 4) × 90° = 14 × 90° = 1260°.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A theodolite with its horizontal axis 1.5 m above the ground is set 50 m from the base of a tower on level ground. The angle of elevation to the top is 45°. The height of the tower is:
सही उत्तर: क) 51.5 m
Height above the instrument axis = 50 tan 45° = 50 m; adding the instrument height gives 51.5 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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If the angle of elevation of a point is 30°, its zenith angle is:
सही उत्तर: ख) 60°
Zenith angle = 90° − angle of elevation = 90° − 30° = 60°.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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