इन्जिनियरिङ सेवा सब-इन्जिनियर (पाँचौँ तह) – प्राविधिक पत्र
इन्जिनियरिङ सेवा – सब-इन्जिनियर (पाँचौँ तह)
Sub-Engineer – 5th Level · Engineering Service
१,९४० प्रश्न उपलब्ध। मोड छान्नुहोस्:
प्राविधिक पत्र: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ५ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A vertical curve formed where a falling (descending) gradient meets a rising (ascending) gradient is a:
सही उत्तर: ख) Valley (sag) curve
Valley or sag curves occur where the road changes from down-grade to up-grade, forming a low point.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Superelevation (cant) is provided on horizontal curves of roads and railways to:
सही उत्तर: ग) Counteract the effect of centrifugal force on vehicles
Raising the outer edge introduces a component of weight towards the centre, balancing centrifugal force.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The shift of a circular curve due to a transition curve of length L and radius R is approximately L²/(24R). For L = 60 m and R = 300 m, the shift is:
सही उत्तर: घ) 0.5 m
Shift = 60² / (24 × 300) = 3600 / 7200 = 0.5 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A curve consisting of two circular arcs bending in opposite directions, with a common tangent at the junction, is a:
सही उत्तर: ग) Reverse curve
In a reverse (serpentine) curve, the arcs curve in opposite directions; a compound curve bends in the same direction.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The point of intersection of two straights has chainage 1000.0 m and the tangent length of the curve is 109.2 m. The chainage of the point of curvature (beginning of curve) is:
सही उत्तर: ख) 890.8 m
Chainage of PC = chainage of PI − tangent length = 1000.0 − 109.2 = 890.8 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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For a simple circular curve of radius 200 m and deflection angle 60°, the apex distance R(sec Δ/2 − 1) is about:
सही उत्तर: क) 30.9 m
Apex distance = 200 (sec 30° − 1) = 200 (1.1547 − 1) ≈ 30.9 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Trilateration differs from triangulation in that, in trilateration:
सही उत्तर: घ) The lengths of the sides of triangles are measured (e.g. by EDM) instead of mainly angles
With EDM, all sides can be measured directly and angles computed, which is trilateration.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Spherical excess in a spherical triangle amounts to about 1 second for every:
सही उत्तर: क) 196 km² of area
Spherical excess ≈ 1" per 196 km², so it matters only in large geodetic triangles.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In triangulation, the 'phase correction' is applied because:
सही उत्तर: क) One side of a cylindrical signal is illuminated by the sun, so the observer bisects the bright part rather than the centre
Phase is the error of bisecting the apparently brighter portion of a signal; the correction reduces the sight to the signal's centre.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In triangulation, a satellite station is used when:
सही उत्तर: ग) The main station cannot be occupied by the instrument although it can be sighted
An eccentric (satellite) station is set up close to the main station and observations are reduced to the main station.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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