इन्जिनियरिङ सेवा सब-इन्जिनियर (पाँचौँ तह) – प्राविधिक पत्र
इन्जिनियरिङ सेवा – सब-इन्जिनियर (पाँचौँ तह)
Sub-Engineer – 5th Level · Engineering Service
५०३ प्रश्न उपलब्ध। मोड छान्नुहोस्:
प्राविधिक पत्र: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ५ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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The trap in a sanitary fitting mainly serves to:
सही उत्तर: ग) Prevent foul gases from entering the building by a water seal
The water held in a trap forms a seal that blocks sewer gases.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Crown corrosion of concrete sewers is caused mainly by:
सही उत्तर: घ) Hydrogen sulphide gas
H2S from septic sewage is oxidised to sulphuric acid on the sewer crown, which attacks concrete.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The hydraulic mean radius of a circular pipe running full of diameter D is:
सही उत्तर: क) D/4
R = area / wetted perimeter = (pi D^2/4) / (pi D) = D/4.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A sewer flows with Manning's n = 0.013, hydraulic radius 0.1 m and bed slope 0.004. The velocity of flow is about:
सही उत्तर: ख) 1.05 m/s
V = (1/n) R^(2/3) S^(1/2) = (1/0.013) x 0.215 x 0.0632 = about 1.05 m/s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The minimum velocity in a sewer that prevents solids from settling is called the:
सही उत्तर: ख) Self-cleansing velocity
Sewers are designed for at least the self-cleansing velocity so that solids do not deposit.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A sewer system that carries both domestic sewage and storm water in the same conduit is called the:
सही उत्तर: ग) Combined system
A combined system uses one set of sewers for both sewage and rainwater.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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By the rational method, the peak runoff from 12 ha with runoff coefficient 0.6 and rainfall intensity 50 mm/h is:
सही उत्तर: घ) 1.0 m3/s
Q = CIA/360 = 0.6 x 50 x 12 / 360 = 1.0 m3/s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A town of 20,000 people is supplied with 135 litres per capita per day. If 80% of the water becomes sewage, the daily sewage flow is:
सही उत्तर: क) 2.16 MLD
Sewage = 0.8 x 135 x 20,000 = 2,160,000 L/day = 2.16 MLD.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A sewage has ultimate BOD of 200 mg/L and a rate constant k = 0.23 per day (base e). Its 5-day BOD is about:
सही उत्तर: क) 137 mg/L
BOD5 = L0(1 - e^(-kt)) = 200(1 - e^(-1.15)) = about 137 mg/L.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a BOD test, 6 mL of sewage is diluted to 300 mL. Initial DO is 8.0 mg/L and DO after 5 days is 4.0 mg/L. The BOD is:
सही उत्तर: ख) 200 mg/L
BOD = (DO drop) x dilution factor = (8.0 - 4.0) x 300/6 = 200 mg/L.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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