आधारभूत विद्युत् (Basic Electrical) – Basic Electrical Engineering MCQ
आधारभूत विद्युत् (Basic Electrical) – इलेक्ट्रिकल र टेलिकम
Basic Electrical Engineering · Technical – Electrical, Mechanical & Telecom · २,२९९ प्रश्न
२,२९९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
आधारभूत विद्युत् (Basic Electrical): प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
-
A consumer is billed under a two-part tariff of Rs 100 fixed charge per month plus Rs 9 per unit. If 150 units are used in a month, the bill is:
सही उत्तर: ख) Rs 1450
Bill = 100 + 150 × 9 = 100 + 1350 = Rs 1450.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
At the same supply voltage, heater element A alone gives 600 W and element B alone gives 400 W. When the two are connected in series across that supply, the total power is:
सही उत्तर: ख) 240 W
R ∝ 1/P, so in series 1/P = 1/600 + 1/400, giving P = 240 W.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 2 kW kettle of 85% efficiency heats 2 litres of water from 15 °C to 100 °C (c = 4200 J/kg °C). The time taken is about:
सही उत्तर: क) 7 minutes
Heat needed = 2 × 4200 × 85 = 714000 J; useful power = 0.85 × 2000 = 1700 W; t = 714000/1700 = 420 s = 7 min.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
In a circuit, a 6 V source with 2 Ω internal resistance feeds a load. If the terminal voltage is 4 V, the load resistance is:
सही उत्तर: घ) 4 Ω
Current = (6 − 4)/2 = 1 A, so R_L = 4/1 = 4 Ω.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
Going round a closed loop, the voltage rises are 12 V and 5 V and the drops across two resistors are 7 V and V_x. By KVL, V_x equals:
सही उत्तर: ग) 10 V
Σ rises = Σ drops: 12 + 5 = 7 + V_x, so V_x = 10 V.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A connected network has 9 branches and 6 nodes. The numbers of tree branches (twigs) and links are respectively:
सही उत्तर: ग) 5 and 4
Twigs = n − 1 = 5 and links = b − n + 1 = 9 − 6 + 1 = 4.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A Norton equivalent consists of a 2 A current source in parallel with 10 Ω. The equivalent Thevenin circuit is:
सही उत्तर: क) 20 V in series with 10 Ω
V_th = I_N R_N = 2 × 10 = 20 V, and R_th = R_N = 10 Ω.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
In a bridge network, A–C = 1 Ω, C–B = 2 Ω, A–D = 2 Ω, D–B = 1 Ω, and a 1 Ω resistor joins C and D. The equivalent resistance between A and B is:
सही उत्तर: घ) 1.4 Ω
The bridge is unbalanced (1/2 ≠ 2/1). Converting the delta A–C–D (1, 1, 2 Ω) to star or using nodal analysis with 1 A injected gives V_AB = 1.4 V, so R_AB = 1.4 Ω.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 12 V source with 2 Ω series resistance and a 6 V source with 2 Ω series resistance are both connected to a common node, which is joined to the common negative through a 4 Ω load. The load current is:
सही उत्तर: ख) 1.8 A
Node voltage V = (12/2 + 6/2)/(1/2 + 1/2 + 1/4) = 9/1.25 = 7.2 V, so the load current is 7.2/4 = 1.8 A.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 12 V source with internal resistance 1 Ω supplies a 3 Ω load. The efficiency of power transfer is:
सही उत्तर: क) 75%
η = R_L/(R_L + r) = 3/4 = 75% (the load gets 9 × 3 = 27 W out of 36 W generated).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।