आधारभूत विद्युत् (Basic Electrical) – Basic Electrical Engineering MCQ
आधारभूत विद्युत् (Basic Electrical) – इलेक्ट्रिकल र टेलिकम
Basic Electrical Engineering · Technical – Electrical, Mechanical & Telecom · २,२९९ प्रश्न
२,२९९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
आधारभूत विद्युत् (Basic Electrical): प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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In a delta-connected three-phase system, the line voltage is:
सही उत्तर: ख) equal to the phase voltage
Each phase winding is connected directly between two lines, so V_L = V_ph in delta.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a balanced three-phase star-connected system, the current in the neutral wire is:
सही उत्तर: ख) zero
The three balanced phase currents are 120 degrees apart and add up to zero.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a series RC circuit, the current:
सही उत्तर: ग) leads the applied voltage by an angle between 0 and 90 degrees
The capacitive reactance makes the current lead, but the resistance keeps the angle below 90 degrees.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A major disadvantage of operating a load at a low power factor is that:
सही उत्तर: क) it draws more current for the same active power, increasing losses
I = P / (V cos phi), so a lower power factor needs more current and causes larger I^2 R losses.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The reciprocal of impedance in an AC circuit is called:
सही उत्तर: क) admittance
Admittance Y = 1/Z, measured in siemens; its imaginary part is susceptance.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A pure inductor of reactance 23 ohm is connected to a 230 V AC supply. The current drawn is:
सही उत्तर: क) 10 A
I = V / X_L = 230 / 23 = 10 A.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Multiplying a phasor by the operator j rotates it by:
सही उत्तर: ग) 90 degrees counter-clockwise
j = 1 at an angle of 90 degrees, so multiplication by j advances the phasor by 90 degrees.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The impedance Z = 3 + j4 ohm has a magnitude and phase angle of about:
सही उत्तर: घ) 5 ohm at 53.13 degrees
|Z| = sqrt(9 + 16) = 5 and angle = tan^-1(4/3) = 53.13 degrees.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The power factor of a purely capacitive circuit is:
सही उत्तर: घ) zero (leading)
Current leads voltage by 90 degrees, so cos 90 degrees = 0 and it is called leading.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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At a frequency below the resonant frequency, a series RLC circuit behaves as a/an:
सही उत्तर: क) capacitive circuit
Below resonance X_C > X_L, so the net reactance is capacitive and current leads the voltage.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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