आधारभूत विद्युत् (Basic Electrical) – Basic Electrical Engineering MCQ
आधारभूत विद्युत् (Basic Electrical) – इलेक्ट्रिकल र टेलिकम
Basic Electrical Engineering · Technical – Electrical, Mechanical & Telecom · २,२९९ प्रश्न
२,२९९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
आधारभूत विद्युत् (Basic Electrical): प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
-
The low lagging power factor of an industrial installation is commonly improved by connecting:
सही उत्तर: ख) capacitors in parallel with the load
Shunt capacitors supply leading reactive power that offsets the lagging reactive power of inductive loads.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
At resonance, the impedance of an ideal parallel LC (tank) circuit is:
सही उत्तर: ख) maximum
In a parallel resonant circuit the branch currents cancel, so line current is minimum and impedance is maximum.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The resonant frequency of a series LC circuit is given by:
सही उत्तर: ग) 1 / (2 pi sqrt(LC))
Resonance occurs when 2 pi f L = 1 / (2 pi f C), giving f0 = 1 / (2 pi sqrt(LC)).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
At resonance in a series RLC circuit, the impedance of the circuit is:
सही उत्तर: क) minimum and equal to R
At resonance X_L = X_C and they cancel, leaving Z = R, the minimum value, so current is maximum.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The average power consumed over a full cycle by an ideal (pure) inductor connected to an AC supply is:
सही उत्तर: क) zero
With a 90° phase difference, cos phi = 0; energy stored in one quarter-cycle is returned in the next, so average power is zero.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A load draws 10 kVA at a power factor of 0.8 lagging. Its active power is:
सही उत्तर: क) 8 kW
P = S x cos phi = 10 x 0.8 = 8 kW.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The unit of reactive power is the:
सही उत्तर: ग) volt-ampere reactive (VAR)
Reactive power Q = V I sin phi is measured in VAR; apparent power is in VA and active power in W.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The active (true) power in a single-phase AC circuit is given by:
सही उत्तर: घ) V I cos phi
Only the in-phase component of current does real work, so P = V I cos phi watts.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A series AC circuit has R = 3 ohm and reactance X = 4 ohm. Its power factor is:
सही उत्तर: घ) 0.6
Z = sqrt(9 + 16) = 5 ohm; power factor = R / Z = 3 / 5 = 0.6.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A series RL circuit has R = 6 ohm and X_L = 8 ohm. Its impedance is:
सही उत्तर: क) 10 ohm
Z = sqrt(R^2 + X_L^2) = sqrt(36 + 64) = 10 ohm.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।