आधारभूत विद्युत् (Basic Electrical) – Basic Electrical Engineering MCQ
आधारभूत विद्युत् (Basic Electrical) – इलेक्ट्रिकल र टेलिकम
Basic Electrical Engineering · Technical – Electrical, Mechanical & Telecom · २,२९९ प्रश्न
२,२९९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
आधारभूत विद्युत् (Basic Electrical): प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
-
Six cells, each of emf 2 V and internal resistance 0.1 ohm, are connected in series to a 4.4 ohm load. The current is:
सही उत्तर: ख) 2.4 A
Total emf = 12 V, total resistance = 4.4 + 0.6 = 5 ohm, so I = 2.4 A.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 12 V source of internal resistance 4 ohm supplies a 2 ohm load. The power delivered to the load is:
सही उत्तर: ख) 8 W
I = 12/(4 + 2) = 2 A, so P = I²R = 4 × 2 = 8 W (slightly less than the 9 W obtainable with a matched 4 ohm load).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A node is connected through 2 ohm to the positive terminal of a 10 V source (negative grounded), and through two separate 4 ohm resistors to ground. The node voltage is:
सही उत्तर: क) 5 V
KCL: (10 − V)/2 = V/4 + V/4, so 10 − V = V and V = 5 V.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 10 V source in series with 2 ohm feeds two 4 ohm resistors connected in parallel. The current in each 4 ohm resistor is:
सही उत्तर: घ) 1.25 A
R_total = 2 + 2 = 4 ohm, so I = 2.5 A, which splits equally: 1.25 A each.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 12 V source with 3 ohm series resistance has a 6 ohm resistor across its terminals. The Norton equivalent current is:
सही उत्तर: ग) 4 A
Shorting the terminals shorts the 6 ohm resistor, so I_N = 12/3 = 4 A (with R_N = 3 ∥ 6 = 2 ohm).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A network has Thevenin voltage 18 V and Thevenin resistance 3 ohm (from a 24 V source, 4 ohm series, 12 ohm shunt). The maximum power it can deliver to a load resistor is:
सही उत्तर: ग) 27 W
Maximum power = V_th²/(4R_th) = 324/12 = 27 W, with the load set to 3 ohm.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 24 V source with a 4 ohm series resistance has a 12 ohm resistor connected across its output terminals. The Thevenin voltage at the terminals is:
सही उत्तर: क) 18 V
Open-circuit voltage = 24 × 12/(4 + 12) = 18 V.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
n identical resistors of R each give 50 ohm in series and 2 ohm in parallel. The values of n and R are:
सही उत्तर: घ) n = 5, R = 10 ohm
nR = 50 and R/n = 2, so R² = 100, R = 10 ohm and n = 5.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
Converting a delta with sides 6 ohm (A–B), 6 ohm (B–C) and 12 ohm (C–A) into an equivalent star, what resistance appears in the star arm at terminal A?
सही उत्तर: ख) 3 ohm
R_A = R_AB × R_CA/(R_AB + R_BC + R_CA) = 6 × 12/24 = 3 ohm.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 12 V supply feeds a 4 kilo-ohm and an 8 kilo-ohm resistor in series. A voltmeter of 8 kilo-ohm resistance is connected across the 8 kilo-ohm resistor. It reads:
सही उत्तर: क) 6 V
The voltmeter in parallel makes 4 kilo-ohm, so the voltage divides equally: 6 V (instead of the true 8 V).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।