आधारभूत विद्युत् (Basic Electrical) – Basic Electrical Engineering MCQ
आधारभूत विद्युत् (Basic Electrical) – इलेक्ट्रिकल र टेलिकम
Basic Electrical Engineering · Technical – Electrical, Mechanical & Telecom · २,२९९ प्रश्न
२,२९९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
आधारभूत विद्युत् (Basic Electrical): प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A 10 V source with 5 ohm series resistance and a 2 A current source both feed a node that is connected to ground through 5 ohm. Using superposition, the node voltage is:
सही उत्तर: ख) 10 V
Voltage source alone: 10 × 5/10 = 5 V. Current source alone: 2 × (5 parallel 5) = 5 V. Total = 10 V.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Resistors of 2 ohm, 4 ohm and 6 ohm are in series across a 24 V supply. The voltage across the 4 ohm resistor is:
सही उत्तर: ख) 8 V
I = 24/12 = 2 A, so V = 2 × 4 = 8 V.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A battery has an emf of 12 V and a short-circuit current of 30 A. Its internal resistance is:
सही उत्तर: ग) 0.4 ohm
r = E/I_sc = 12/30 = 0.4 ohm.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a single loop, a 12 V source and a 4 V source act in opposition, and the loop resistance is 2 ohm + 6 ohm. The loop current is:
सही उत्तर: घ) 1 A
By KVL, I = (12 − 4)/(2 + 6) = 1 A.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A battery of emf 12 V and internal resistance 0.4 ohm is being charged from a 14 V DC supply. The charging current is:
सही उत्तर: क) 5 A
The net driving voltage is 14 − 12 = 2 V, so I = 2/0.4 = 5 A.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Four cells, each of emf 1.5 V and internal resistance 0.5 ohm, are connected in series to a 4 ohm resistor. The current is:
सही उत्तर: क) 1 A
Total emf 6 V, total internal resistance 2 ohm: I = 6/(2 + 4) = 1 A.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A cell reads 1.5 V on open circuit and 1.2 V when it supplies 0.3 A. Its internal resistance is:
सही उत्तर: ख) 1 ohm
Internal drop = 1.5 − 1.2 = 0.3 V at 0.3 A, so r = 1 ohm.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Branches with conductances of 0.2 S and 0.3 S are connected in parallel. The equivalent resistance is:
सही उत्तर: ग) 2 ohm
Conductances in parallel add: G = 0.5 S, so R = 1/0.5 = 2 ohm.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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An aluminium conductor 1 km long has a cross-section of 10 mm². Taking resistivity as 2.8 x 10^-8 ohm-m, its resistance is:
सही उत्तर: घ) 2.8 ohm
R = rho L/A = 2.8 x 10^-8 × 1000/(10 x 10^-6) = 2.8 ohm.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A copper coil has a resistance of 10 ohm at 20 °C. Taking alpha(20) = 0.00393 per °C, its resistance at 70 °C is about:
सही उत्तर: घ) 11.97 ohm
R = 10(1 + 0.00393 × 50) = 10 × 1.1965 ≈ 11.97 ohm.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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