IT प्रवेश – B.Sc. CSIT, BIT, BCA
IT प्रवेश – B.Sc. CSIT, BIT, BCA
IT Entrance – B.Sc. CSIT, BIT & BCA · २,५९२ प्रश्न
२,५९२ प्रश्न उपलब्ध। मोड छान्नुहोस्:
IT प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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When a sound source moves towards a stationary listener, the frequency heard by the listener:
सही उत्तर: ग) Increases
By the Doppler effect, approach compresses the waves and raises the apparent frequency (pitch). When the source moves away the apparent frequency decreases.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A wave has frequency 500 Hz and wavelength 0.68 m. Its speed is:
सही उत्तर: क) 340 m/s
Wave speed v = fλ = 500 × 0.68 = 340 m/s. Dividing instead of multiplying gives an incorrect result.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The speed of sound in an ideal gas is proportional to (T = absolute temperature):
सही उत्तर: घ) √T
v = √(γRT/M), so v ∝ √T. This is why sound travels faster in warm air than in cold air.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Sound waves travelling through air are:
सही उत्तर: ग) Longitudinal waves
In air the particles vibrate along the direction of propagation, forming compressions and rarefactions, so sound is longitudinal. Unlike electromagnetic waves, sound needs a material medium.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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For a particle in simple harmonic motion, at the mean (equilibrium) position:
सही उत्तर: क) Velocity is maximum
At the mean position the displacement is zero, so acceleration (−ω²x) is zero and velocity is maximum. Acceleration is maximum at the extreme positions.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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If the length of a simple pendulum is made four times, its time period becomes:
सही उत्तर: घ) Two times
Since T ∝ √l, increasing l four times increases T by √4 = 2 times. The period does not depend on the mass of the bob.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A simple pendulum has length 1 m. Taking g = π² m/s², its time period is:
सही उत्तर: ग) 2 s
T = 2π√(l/g) = 2π√(1/π²) = 2π × (1/π) = 2 s. Such a pendulum (period 2 s) is called a seconds pendulum.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Water flows at 2 m/s through a pipe of cross-sectional area 4 cm². Where the area narrows to 1 cm², the speed of the water is:
सही उत्तर: ख) 8 m/s
By the equation of continuity A₁v₁ = A₂v₂, v₂ = 4 × 2 / 1 = 8 m/s. Speed increases where the pipe narrows, so 0.5 m/s is the reverse calculation.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A hydraulic lift works on the principle of:
सही उत्तर: क) Pascal's law
Pascal's law states that pressure applied to an enclosed fluid is transmitted equally in all directions, so a small force on a small piston gives a large force on a large piston. Archimedes' principle deals with buoyancy.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Bernoulli's theorem for fluid flow is based on the conservation of:
सही उत्तर: घ) Energy
Bernoulli's equation P + ½ρv² + ρgh = constant expresses conservation of energy per unit volume. Conservation of mass gives the equation of continuity, A₁v₁ = A₂v₂.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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