गणित – Mathematics MCQ
गणित – डिप्लोमा प्रवेश
Mathematics · CTEVT Diploma Engineering Entrance · ७५१ प्रश्न
७५१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
गणित: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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What principal will earn Rs 1,800 simple interest in 3 years at 12% per annum?
सही उत्तर: ख) Rs 5,000
P = (I × 100)/(T × R) = (1800 × 100)/(3 × 12) = Rs 5,000. Always divide by the product of time and rate.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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At simple interest, a sum of money doubles itself in 8 years. The rate of interest per annum is:
सही उत्तर: ग) 12.5%
Doubling means interest = principal, so R = 100 / 8 = 12.5% per annum. Rule: rate × time = 100 when a sum doubles at simple interest.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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An article is sold for Rs 450 at a loss of 10%. Its cost price is:
सही उत्तर: ग) Rs 500
SP = 90% of CP, so CP = 450 / 0.9 = Rs 500. Rs 495 wrongly adds 10% of the SP to the SP.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Two successive discounts of 20% and 10% are equivalent to a single discount of:
सही उत्तर: घ) 28%
Remaining price = 0.80 × 0.90 = 0.72 of the marked price, so the single discount is 28%. Simply adding gives 30%, which is wrong because the second discount is on a reduced price.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The marked price of a jacket is Rs 2,000. A 15% discount is allowed and then 13% VAT is added. The price the customer pays is:
सही उत्तर: क) Rs 1,921
Price after discount = 2000 × 0.85 = 1700; with VAT = 1700 × 1.13 = Rs 1,921. Rs 1,700 forgets the VAT, and Rs 2,260 forgets the discount.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A shopkeeper buys an article for Rs 400 and sells it for Rs 500. His profit percent is:
सही उत्तर: ख) 25%
Profit = 100 on cost 400, so profit% = 100/400 × 100 = 25%. 20% is profit as a percentage of selling price, which is not the standard definition.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The population of a town is 20,000 and it increases at 5% per year. The population after 2 years will be:
सही उत्तर: ख) 22,050
P = 20000 × (1.05)² = 22,050. 22,000 is obtained by adding only 5% of the original population each year, ignoring growth on growth.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A machine bought for Rs 50,000 depreciates at 10% per annum. Its value after 2 years is:
सही उत्तर: ग) Rs 40,500
Depreciated value = 50000 × (1 − 0.10)² = 50000 × 0.81 = Rs 40,500. Rs 40,000 wrongly subtracts 10% of the original price each year (simple depreciation).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Rs 10,000 is deposited at 10% per annum compound interest, compounded half-yearly. The amount after 1 year is:
सही उत्तर: घ) Rs 11,025
Half-yearly: rate = 5% per period and 2 periods, so A = 10000 × (1.05)² = Rs 11,025. Rs 11,000 would be the yearly-compounded (or simple interest) amount.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A sum of Rs 8,000 is invested at 5% per annum compound interest, compounded yearly. The compound interest after 3 years is:
सही उत्तर: क) Rs 1,261
Amount = 8000 × (1.05)³ = Rs 9,261, so CI = 9261 − 8000 = Rs 1,261. Rs 1,200 is the simple interest, and Rs 9,261 is the amount, not the interest.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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