इन्जिनियरिङ प्रवेश – Mathematics, Physics, Chemistry, English
इन्जिनियरिङ प्रवेश – Mathematics, Physics, Chemistry, English
Engineering Entrance – Mathematics, Physics, Chemistry & English · ३,८४१ प्रश्न
३,८४१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
इन्जिनियरिङ प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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Four particles, each of mass 1 kg, are at the corners of a square of side 2 m. Their moment of inertia about an axis through the centre perpendicular to the square is:
सही उत्तर: ख) 8 kg m²
Each particle is at distance a/√2 = √2 m from the centre, so I = 4 × 1 × 2 = 8 kg m².
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A conical pendulum has a string of length 0.8 m making an angle of 60° with the vertical. Its period of revolution is (g = 10 m/s²):
सही उत्तर: क) 0.4π s
T = 2π√(L cos θ/g) = 2π√(0.8 × 0.5/10) = 2π√0.04 = 2π(0.2) = 0.4π s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A car of mass 1000 kg goes over the top of a hump of radius 40 m at 10 m/s. The normal force on the car at the top is (g = 10 m/s²):
सही उत्तर: ग) 7500 N
mg − N = mv²/r ⇒ N = 10000 − 1000 × 100/40 = 10000 − 2500 = 7500 N.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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For a stone of mass m whirled in a vertical circle on a string, the difference between the tensions at the lowest and highest points is:
सही उत्तर: घ) 6mg
T_low − T_high = m(v_low² − v_high²)/r + 2mg = m(4gr)/r + 2mg = 6mg, using energy conservation v_low² − v_high² = 4gr.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 2 kg block sliding at 10 m/s on a horizontal floor comes to rest because of friction (μ = 0.5). The distance it slides is (g = 10 m/s²):
सही उत्तर: क) 10 m
Work–energy: μmg·s = ½mv², so s = v²/(2μg) = 100/10 = 10 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 1000 kg car moves at a steady 20 m/s up a slope rising 1 m in every 20 m of road, against a resistive force of 500 N. The power delivered by its engine is (g = 10 m/s²):
सही उत्तर: ख) 20 kW
Required force = mg sin θ + 500 = 1000 × 10 × (1/20) + 500 = 1000 N; P = Fv = 1000 × 20 = 20 kW.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A ball is dropped from a height of 20 m onto a hard floor. If the coefficient of restitution is 0.5, the height it reaches after the second bounce is:
सही उत्तर: ख) 1.25 m
Each bounce multiplies the height by e² = 0.25: 20 → 5 m → 1.25 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A force F = 3x² N acts along the x-axis. The work it does in moving a body from x = 0 to x = 2 m is:
सही उत्तर: क) 8 J
W = ∫₀² 3x² dx = [x³]₀² = 8 J.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Sand drops vertically at 2 kg/s onto a conveyor belt moving horizontally at a constant 3 m/s. The extra horizontal force needed to keep the belt moving is:
सही उत्तर: घ) 6 N
F = v(dm/dt) = 3 × 2 = 6 N, the rate at which horizontal momentum is given to the sand.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 60 kg man jumps horizontally off a stationary 120 kg boat with a speed of 3 m/s. Neglecting water resistance, the boat moves back with a speed of:
सही उत्तर: ग) 1.5 m/s
Momentum is conserved: 60 × 3 = 120 × v, so v = 1.5 m/s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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