आईओई इन्जिनियरिङ प्रवेश (त्रिवि) BE / B.Arch प्रवेश परीक्षा तयारी
आईओई इन्जिनियरिङ प्रवेश (त्रिवि) – BE / B.Arch प्रवेश परीक्षा
IOE BE / B.Arch Entrance · IOE Entrance (TU)
३,८४१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
BE/B.Arch प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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An object is placed 15 cm from a convex lens of focal length 10 cm. The magnification produced is:
सही उत्तर: ख) −2
1/v = 1/10 − 1/15 = 1/30 gives v = 30 cm, so m = v/u = 30/(−15) = −2 (real, inverted).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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When an object lies between the pole and the focus of a concave mirror, 10 cm from a mirror of focal length 20 cm, the image formed is:
सही उत्तर: घ) virtual, erect and twice the size of the object
1/v = 1/f − 1/u = −1/20 + 1/10 = 1/20 (Cartesian), so v = +20 cm behind the mirror and m = −v/u = 2: virtual, erect, magnified.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The speed of sound in air at 0 °C is 332 m/s. Its speed at 91 °C is about:
सही उत्तर: क) 383 m/s
v ∝ √T: v = 332 × √(364/273) ≈ 332 × 1.155 ≈ 383 m/s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A siren of 660 Hz recedes from a listener at rest with a speed of 30 m/s. Taking the speed of sound as 330 m/s, the listener hears a pitch of:
सही उत्तर: ग) 605 Hz
f′ = f v/(v + v_s) = 660 × 330/360 = 605 Hz.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A string 0.6 m long, fixed at both ends, carries waves at 240 m/s. The frequency of its third harmonic is:
सही उत्तर: घ) 600 Hz
fₙ = nv/2L = 3 × 240/1.2 = 600 Hz.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A pipe 1 m long is open at both ends. If the speed of sound is 340 m/s, the frequency of its third harmonic is:
सही उत्तर: ग) 510 Hz
fₙ = nv/2L = 3 × 340/2 = 510 Hz.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a resonance-tube experiment with a 500 Hz tuning fork, the first resonance occurs at an air-column length of 17 cm (neglect end correction). The speed of sound is:
सही उत्तर: ख) 340 m/s
First resonance: L = λ/4, so λ = 0.68 m and v = fλ = 500 × 0.68 = 340 m/s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Two slabs of equal thickness and area with conductivities K and 2K are joined face to face. The outer faces are at 100 °C (on the K side) and 0 °C. In the steady state the interface temperature is:
सही उत्तर: क) 33.3 °C
Equal heat flow: K(100 − T) = 2K(T − 0) gives T = 100/3 ≈ 33.3 °C.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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An ideal gas is taken round a rectangular cycle on a P–V diagram between pressures 1 × 10⁵ Pa and 2 × 10⁵ Pa and volumes 1 L and 3 L. The net work done per cycle is:
सही उत्तर: ग) 200 J
Net work = enclosed area = (2 − 1) × 10⁵ Pa × (3 − 1) × 10⁻³ m³ = 200 J.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A monatomic ideal gas (γ = 5/3) expands adiabatically to twice its volume. Its absolute temperature becomes about:
सही उत्तर: घ) 0.63 times
TV^{γ−1} = constant: T₂/T₁ = (1/2)^{2/3} ≈ 0.63.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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