आईओई इन्जिनियरिङ प्रवेश (त्रिवि) BE / B.Arch प्रवेश परीक्षा तयारी
आईओई इन्जिनियरिङ प्रवेश (त्रिवि) – BE / B.Arch प्रवेश परीक्षा
IOE BE / B.Arch Entrance · IOE Entrance (TU)
३,८४१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
BE/B.Arch प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A wire of resistance R is stretched uniformly to double its length (volume constant). Its new resistance is:
सही उत्तर: ग) 4R
Doubling length halves the area, so R = ρL/A becomes ρ(2L)/(A/2) = 4R. 2R ignores the reduction in area.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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An electric dipole placed in a uniform electric field experiences:
सही उत्तर: ख) Zero net force but possibly a torque
The forces qE and −qE on the two charges are equal and opposite, so net force is zero, but they can form a couple with torque τ = pE sinθ.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The electric potential at a distance of 9 cm from a point charge of 1 μC is (1/4πε₀ = 9 × 10⁹ N m² C⁻²):
सही उत्तर: क) 1 × 10⁵ V
V = kq/r = 9 × 10⁹ × 10⁻⁶ / 0.09 = 10⁵ V. Remember V ∝ 1/r, whereas the field E ∝ 1/r².
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The energy stored in a 10 μF capacitor charged to 100 V is:
सही उत्तर: ग) 0.05 J
U = ½CV² = ½ × 10 × 10⁻⁶ × 100² = 0.05 J. 0.1 J results from omitting the factor ½.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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When a dielectric slab of dielectric constant K completely fills the space between the plates of a parallel-plate capacitor, its capacitance:
सही उत्तर: ख) Becomes K times
C = Kε₀A/d, so capacitance increases K times. For an isolated charged capacitor, the potential difference then decreases by K.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The electric field inside a charged hollow conducting sphere is:
सही उत्तर: क) Zero
All charge resides on the outer surface, and by Gauss's law the enclosed charge is zero, so E = 0 inside. The potential inside, however, is constant and non-zero.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A coin at the bottom of a 12 cm deep tank of water (refractive index 4/3) appears raised. Its apparent depth when viewed from above is:
सही उत्तर: घ) 9 cm
Apparent depth = real depth / n = 12/(4/3) = 9 cm. 3 cm is the apparent rise (normal shift), not the apparent depth.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Two coherent light waves meet with a path difference of λ/2. The result at that point is:
सही उत्तर: ग) Destructive interference (dark)
A path difference of λ/2 corresponds to a phase difference of π, so the waves cancel. Constructive interference needs a path difference of nλ.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The polarizing (Brewster's) angle for a glass of refractive index √3 is:
सही उत्तर: ख) 60°
Brewster's law: tan θp = n = √3, so θp = 60°. At this angle the reflected and refracted rays are perpendicular.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The phenomenon of polarization shows that light waves are:
सही उत्तर: क) Transverse
Only transverse waves can be polarized because their vibrations can be restricted to one plane. Sound waves in air, being longitudinal, cannot be polarized.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
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