आईओई इन्जिनियरिङ प्रवेश (त्रिवि) M.Sc. इन्जिनियरिङ प्रवेश तयारी
आईओई इन्जिनियरिङ प्रवेश (त्रिवि) – M.Sc. इन्जिनियरिङ प्रवेश
IOE M.Sc. Engineering Entrance · IOE Entrance (TU)
३,८४१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
BE/B.Arch प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
-
The loss of strength of a material after it has been subjected to repeated alternating strain is called:
सही उत्तर: क) elastic fatigue
Elastic fatigue is the weakening caused by repeated cycles of stress, as in a wire bent back and forth until it breaks.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A pendulum bob is a hollow sphere full of water that slowly leaks out through a small hole at the bottom. As the water drains, the period of the pendulum:
सही उत्तर: ग) first increases and then decreases
As water leaves, the centre of mass first moves down (effective length increases) and then moves back up to the centre when the sphere is empty, so T first increases and then decreases to its original value.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A simple pendulum is taken inside an artificial satellite orbiting the Earth. Its time period becomes:
सही उत्तर: घ) infinite (it does not oscillate)
In free fall the effective g is zero, so T = 2π√(l/g_eff) becomes infinite: the bob does not swing back.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The orbital speed of a satellite in a circular orbit of given radius around the Earth:
सही उत्तर: ख) does not depend on the mass of the satellite
v₀ = √(GM/r) contains only the Earth's mass M and the orbit radius r.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The relation between gravitational field intensity E and gravitational potential V at a distance r is:
सही उत्तर: ख) E = −dV/dr
Field intensity is the negative gradient of potential, E = −dV/dr.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
According to Kepler's second law, the areal velocity of a planet is constant and equal to (L = angular momentum, m = mass of the planet):
सही उत्तर: क) L/(2m)
dA/dt = ½r²(dθ/dt) = L/(2m), constant because the gravitational force is central and conserves L.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The binding energy of a satellite of mass m in a circular orbit of radius r around the Earth (mass M) is:
सही उत्तर: ग) GMm/(2r)
Total energy E = −GMm/(2r); the energy needed to free it completely (binding energy) is GMm/(2r).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The centre of mass of a uniform solid right circular cone of height h lies on its axis at a distance from the base of:
सही उत्तर: ख) h/4
For a solid cone the centre of mass is at h/4 above the base (3h/4 from the apex); h/3 is for a hollow conical shell or a triangular lamina.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The centre of mass of a uniform solid hemisphere of radius R lies on its axis at a distance from the centre of its flat face of:
सही उत्तर: क) 3R/8
Summing thin circular discs gives z̄ = 3R/8 for a solid hemisphere (R/2 for a hollow hemispherical shell).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The centre of mass of a uniform semicircular disc (lamina) of radius R lies on its symmetry axis at a distance from the centre of:
सही उत्तर: क) 4R/(3π)
Integrating over semicircular strips gives ȳ = 4R/(3π) for the semicircular lamina (2R/π is for a semicircular wire).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।