आईओई इन्जिनियरिङ प्रवेश (त्रिवि) M.Sc. इन्जिनियरिङ प्रवेश तयारी
आईओई इन्जिनियरिङ प्रवेश (त्रिवि) – M.Sc. इन्जिनियरिङ प्रवेश
IOE M.Sc. Engineering Entrance · IOE Entrance (TU)
३,८४१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
BE/B.Arch प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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The reciprocal of the bulk modulus of a substance is called its:
सही उत्तर: घ) compressibility
Compressibility = 1/B.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Resonance occurs in a forced oscillation when:
सही उत्तर: ख) the driving frequency equals the natural frequency of the system
At resonance the driving frequency matches the natural frequency and the amplitude becomes maximum.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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For a particle in SHM of amplitude A, the potential energy at displacement A/2 is what fraction of its total energy?
सही उत्तर: ग) 1/4
U = ½kx² = ½k(A/2)² = ¼(½kA²).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The time period of a simple pendulum of length 1 m at a place where g = π² m/s² is:
सही उत्तर: क) 2 s
T = 2π√(l/g) = 2π√(1/π²) = 2 s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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If the Earth were to shrink suddenly to half its present radius, its mass remaining the same, the length of the day would become:
सही उत्तर: ख) 6 hours
Angular momentum is conserved: I ∝ R², so I becomes 1/4 and ω becomes 4 times; T = 24/4 = 6 h.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The moment of inertia of a thin ring of mass M and radius R about a tangent lying in its plane is:
सही उत्तर: घ) 3MR²/2
About a diameter I = MR²/2; by the parallel axis theorem about a tangent in its plane, I = MR²/2 + MR² = 3MR²/2.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The moment of inertia of a uniform solid sphere of mass M and radius R about a tangent is:
सही उत्तर: घ) 7MR²/5
Parallel axis theorem: I = 2MR²/5 + MR² = 7MR²/5.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Two satellites revolve around the Earth in circular orbits of radii r and 4r. The ratio of their time periods is:
सही उत्तर: ख) 1 : 8
T ∝ r^(3/2), so T₁ : T₂ = 1 : 4^(3/2) = 1 : 8.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A planet has the same radius as the Earth but twice its mass. The escape velocity from its surface is:
सही उत्तर: ग) √2 times that from the Earth
vₑ = √(2GM/R) ∝ √M for the same R, so it becomes √2 times.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The escape velocity of a body from the Earth's surface:
सही उत्तर: क) does not depend on the mass of the body
vₑ = √(2GM/R) contains only the Earth's mass and radius, not the mass of the body.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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