आईओई इन्जिनियरिङ प्रवेश (त्रिवि) M.Sc. इन्जिनियरिङ प्रवेश तयारी
आईओई इन्जिनियरिङ प्रवेश (त्रिवि) – M.Sc. इन्जिनियरिङ प्रवेश
IOE M.Sc. Engineering Entrance · IOE Entrance (TU)
३,८४१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
BE/B.Arch प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
-
A ball is acted on by a force that rises linearly from 0 to 100 N in 0.1 s and then falls linearly to 0 in the next 0.1 s. The impulse delivered is:
सही उत्तर: ग) 10 N s
Impulse = area under the F–t graph = ½ × 0.2 s × 100 N = 10 N s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 5 kg block rests on a horizontal floor with μₛ = 0.5. A horizontal push of 10 N is applied. The friction force on the block is (g = 10 m/s²):
सही उत्तर: क) 10 N
Limiting friction is μₛmg = 25 N; since 10 N < 25 N the block stays at rest and static friction just balances the push: 10 N.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 2 kg block on a rough floor (μ = 0.2) is pulled by a 10 N force at 30° above the horizontal. The friction force acting on it while it slides is (g = 10 m/s²):
सही उत्तर: घ) 3 N
N = mg − F sin 30° = 20 − 5 = 15 N, so kinetic friction = μN = 0.2 × 15 = 3 N.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 3 kg block on a smooth 30° incline is tied by a light string over a pulley at the top to a hanging 2 kg mass. The acceleration of the system is (g = 10 m/s²):
सही उत्तर: ख) 1 m/s²
Net force = 2g − 3g sin 30° = 20 − 15 = 5 N on a total mass of 5 kg, so a = 1 m/s².
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A 50 kg person stands in a lift that is moving upward but slowing down at 2 m/s². The normal force from the floor on the person is (g = 10 m/s²):
सही उत्तर: क) 400 N
Moving up while slowing means acceleration is 2 m/s² downward: N = m(g − a) = 50 × 8 = 400 N.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A swimmer can swim at 2 m/s in still water and the river flows at 1 m/s. To reach the point directly opposite, he must head at an angle with the upstream direction of the river bank of:
सही उत्तर: ख) 60°
The upstream component must cancel the current: 2 cos α = 1, so α = 60° with the upstream direction of the bank (30° from the perpendicular).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A ball is projected at 20 m/s at 45° to the horizontal. At a horizontal distance of 20 m from the launch point, its height is (g = 10 m/s²):
सही उत्तर: ग) 10 m
y = x tan θ − gx²/(2u²cos²θ) = 20 − 10(400)/(2 × 400 × 0.5) = 20 − 10 = 10 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A body moving with initial velocity 10 m/s has a uniform acceleration of 2 m/s². The distance it travels during the 5th second is:
सही उत्तर: घ) 19 m
sₙ = u + a(n − ½) = 10 + 2(4.5) = 19 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A car starts from rest, accelerates at 1 m/s² and then decelerates at 2 m/s² to rest. If the whole journey takes 30 s, the maximum speed reached is:
सही उत्तर: ख) 20 m/s
v/1 + v/2 = 30 s gives 3v/2 = 30, so v = 20 m/s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
Two balls are thrown vertically upward from the same point with the same speed of 30 m/s, the second 2 s after the first. They meet at a height of (g = 10 m/s²):
सही उत्तर: घ) 40 m
30t − 5t² = 30(t − 2) − 5(t − 2)² gives t = 4 s (for the first ball), so the height is 120 − 80 = 40 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।