आईओई इन्जिनियरिङ प्रवेश (त्रिवि) M.Sc. इन्जिनियरिङ प्रवेश तयारी
आईओई इन्जिनियरिङ प्रवेश (त्रिवि) – M.Sc. इन्जिनियरिङ प्रवेश
IOE M.Sc. Engineering Entrance · IOE Entrance (TU)
३,८४१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
BE/B.Arch प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A ring and a disc of the same mass and radius roll without slipping with the same linear speed. The ratio of their total kinetic energies (ring : disc) is:
सही उत्तर: घ) 4 : 3
Ring: KE = ½mv² + ½mv² = mv²; disc: KE = ½mv² + ¼mv² = ¾mv²; ratio = 1 : ¾ = 4 : 3.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The angular speed of the hour hand of a clock is about:
सही उत्तर: ख) 1.45 × 10⁻⁴ rad/s
The hour hand turns 2π rad in 12 h = 43200 s, so ω = 2π/43200 ≈ 1.45 × 10⁻⁴ rad/s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The moment of inertia of a uniform disc of mass M and radius R about a tangent perpendicular to its plane is:
सही उत्तर: ग) 3MR²/2
By the parallel axes theorem, I = MR²/2 + MR² = 3MR²/2.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The moment of inertia of a thin uniform ring of mass M and radius R about any diameter is:
सही उत्तर: घ) MR²/2
By the perpendicular axes theorem, I_x + I_y = I_z = MR² and by symmetry I_x = I_y, so I(diameter) = MR²/2.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Springs A and B have force constants 100 N/m and 200 N/m. When each is stretched by the same force, the ratio of the energies stored, E_A : E_B, is:
सही उत्तर: ख) 2 : 1
With the same force F, x = F/k and E = F²/(2k), so E ∝ 1/k: E_A : E_B = 200 : 100 = 2 : 1.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A uniform plank 4 m long of mass 20 kg rests horizontally on supports at its two ends. A 40 kg person stands 1 m from the left end. The reaction at the left support is (g = 10 m/s²):
सही उत्तर: ग) 400 N
Taking moments about the right support: R_L × 4 = 200 × 2 + 400 × 3 = 1600, so R_L = 400 N (and R_R = 600 − 400 = 200 N).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A lift is accelerating upward with acceleration a. A coin is dropped from the lift's ceiling. Its acceleration relative to the lift floor is:
सही उत्तर: क) g + a
Relative to the upward-accelerating lift, the coin's acceleration is g − (−a) = g + a downward (the floor accelerates up towards it).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A ball thrown vertically upward with speed u rises to a maximum height H. Its speed at height H/2 is:
सही उत्तर: क) u/√2
v² = u² − 2g(H/2) = u² − gH = u² − u²/2 = u²/2, so v = u/√2.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A particle moves in a circle with constant speed v. The magnitude of the change in its velocity after half a revolution is:
सही उत्तर: ख) 2v
After half a revolution the velocity has the same magnitude but opposite direction, so |Δv| = |v − (−v)| = 2v.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 0.5 kg ball is projected at 20 m/s at 30° above the horizontal and lands on level ground. The magnitude of the change in its momentum during the flight is:
सही उत्तर: ग) 10 kg m/s
The horizontal component is unchanged; the vertical component reverses from +u sin θ to −u sin θ, so Δp = 2mu sin θ = 2 × 0.5 × 20 × 0.5 = 10 kg m/s (downward).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।