आईओई इन्जिनियरिङ प्रवेश (त्रिवि) M.Sc. इन्जिनियरिङ प्रवेश तयारी
आईओई इन्जिनियरिङ प्रवेश (त्रिवि) – M.Sc. इन्जिनियरिङ प्रवेश
IOE M.Sc. Engineering Entrance · IOE Entrance (TU)
३,८४१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
BE/B.Arch प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
-
Ozonolysis of ethene followed by treatment with Zn/H₂O gives:
सही उत्तर: ख) Two molecules of formaldehyde (HCHO)
Ozonolysis cleaves the C=C bond, and each CH₂= end becomes HCHO. But-2-ene would give two molecules of acetaldehyde.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The enthalpy of neutralisation of a strong acid with a strong base in dilute solution is approximately:
सही उत्तर: क) −57.1 kJ per mole of water formed
The reaction is always essentially H⁺ + OH⁻ → H₂O, releasing about 57.1 kJ per mole of water. Weak acids or bases give smaller values because some energy is used for ionisation.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
Phenolphthalein is suitable for titrating a weak acid against a strong base because it:
सही उत्तर: घ) Changes colour in the basic pH range (about 8–10)
The equivalence point of a weak acid–strong base titration is above pH 7, which matches phenolphthalein's colourless-to-pink change. Methyl orange changes colour in the acidic range and is used for strong acid–weak base titrations.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The degree of unsaturation (double bond equivalent) of benzene (C₆H₆) is:
सही उत्तर: ग) 4
DBE = C − H/2 + 1 = 6 − 3 + 1 = 4 (three C=C bonds plus one ring). Counting only the three double bonds gives the wrong answer, 3.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
Phenol treated with chloroform and aqueous NaOH followed by acidification gives salicylaldehyde. This is the:
सही उत्तर: ख) Reimer–Tiemann reaction
The Reimer–Tiemann reaction introduces a –CHO group at the ortho position of phenol through dichlorocarbene. Kolbe's reaction of sodium phenoxide with CO₂ gives salicylic acid instead.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
An SN2 reaction at a chiral carbon proceeds with:
सही उत्तर: क) Inversion of configuration
In SN2 the nucleophile attacks from the side opposite the leaving group in one step, causing Walden inversion. Racemisation and carbocation formation are typical of SN1.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The bond linking amino acids in proteins is the:
सही उत्तर: घ) Peptide bond (–CO–NH–)
Amino acids join through amide links between –COOH of one and –NH₂ of another, called peptide bonds. Glycosidic bonds link monosaccharides in carbohydrates.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
Glucose is classified as an:
सही उत्तर: ग) Aldohexose
Glucose has six carbons and an aldehyde (–CHO) group, so it is an aldohexose. Fructose, with a ketone group, is a ketohexose.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
Natural rubber is a polymer of:
सही उत्तर: ख) Isoprene
Natural rubber is cis-1,4-polyisoprene (2-methylbuta-1,3-diene). Chloroprene polymerises to the synthetic rubber neoprene.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
Nylon-6,6 is formed by condensation polymerisation of hexamethylenediamine with:
सही उत्तर: क) Adipic acid
Hexamethylenediamine and adipic acid each have six carbons and form polyamide nylon-6,6. Caprolactam is the monomer of nylon-6.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।