पोखरा र पूर्वाञ्चल विश्वविद्यालय PU / PoU BE प्रवेश तयारी
पोखरा र पूर्वाञ्चल विश्वविद्यालय – PU / PoU BE प्रवेश
PU BE Entrance · Pokhara & Purbanchal University BE
३,८४१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
BE/B.Arch प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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In the van der Waals equation, the constant 'a' is a measure of:
सही उत्तर: क) Intermolecular attractive forces
The term a n²/V² corrects pressure for attractive forces between molecules. The constant 'b' corrects for the finite volume of molecules.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A real gas behaves most like an ideal gas under conditions of:
सही उत्तर: घ) High temperature and low pressure
At high temperature intermolecular attractions matter less, and at low pressure the molecules' own volume is negligible. Low temperature and high pressure cause the largest deviations (and favour liquefaction).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The ratio of the rates of diffusion of H₂ and O₂ under the same conditions is:
सही उत्तर: ग) 4 : 1
By Graham's law r ∝ 1/√M, so r(H₂)/r(O₂) = √(32/2) = √16 = 4. 16 : 1 forgets to take the square root.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A gas at 27 °C is heated at constant pressure. At what temperature will its volume become double?
सही उत्तर: ख) 327 °C
By Charles's law V ∝ T (in kelvin): 300 K must become 600 K, which is 327 °C. 54 °C comes from doubling the Celsius temperature, which is wrong.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The number of sigma (σ) and pi (π) bonds in an ethene (C₂H₄) molecule is:
सही उत्तर: क) 5 σ and 1 π
Ethene has four C–H σ bonds and a C=C double bond made of one σ and one π bond, giving 5 σ and 1 π. Forgetting the C–C σ bond gives the wrong count of 4 σ.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Water (H₂O) has a much higher boiling point than hydrogen sulphide (H₂S) mainly because of:
सही उत्तर: घ) Hydrogen bonding in water
Strong intermolecular hydrogen bonds between H₂O molecules need extra energy to break. H₂O actually has a lower molar mass (18) than H₂S (34), so mass cannot explain it.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The hybridisation and shape of BF₃ are:
सही उत्तर: ग) sp², trigonal planar
Boron forms three bonds with no lone pair, using sp² hybrids at 120° in a plane. Trigonal pyramidal shapes (like NH₃) need a lone pair on the central atom.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Which molecule has zero dipole moment?
सही उत्तर: ख) CO₂
CO₂ is linear, so the two equal C=O bond dipoles cancel. SO₂ is bent, so its bond dipoles do not cancel.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The bond order of the superoxide ion (O₂⁻) is:
सही उत्तर: क) 1.5
O₂ has bond order 2; adding one electron to an antibonding π* orbital lowers it by ½ to 1.5. A bond order of 1 belongs to the peroxide ion O₂²⁻.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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According to molecular orbital theory, the bond order of N₂ is:
सही उत्तर: ग) 3
N₂ has 8 bonding and 2 antibonding valence electrons in MO terms (10 and 4 if the 1s electrons are included); bond order = (8 − 2)/2 = 3, a triple bond. Bond order 2 belongs to O₂.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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