भौतिक विज्ञान (Physics) – Physics MCQ
भौतिक विज्ञान (Physics) – CEE प्रवेश
Physics · Medical Entrance (CEE) – Physics, Chemistry, Biology & MAT · ४०७ प्रश्न
४०७ प्रश्न उपलब्ध। मोड छान्नुहोस्:
भौतिक विज्ञान (Physics): प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A particle undergoes simple harmonic motion with an amplitude of 4 cm and a period of 0.8 seconds. What is the maximum velocity of the particle?
सही उत्तर: ख) 4.0 cm/s
The angular frequency (ω) for simple harmonic motion is given by ω = 2π/T, where T is the period. In this case, ω = 2π/(0.8) rad/s. The maximum velocity (v_max) of a particle in SHM is v_max = Aω, where A is the amplitude. So, v_max = (4 cm)(2π/(0.8)) = 10π cm/s which is approximately 31.4cm/s. The most plausible incorrect answer is 8.0 cm/s because it's significantly higher than the calculated maximum velocity.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The refractive index of a prism is 1.5. If a ray of light incident on the prism at a small angle is deviated by 30 degrees, what is the angle of incidence?
सही उत्तर: घ) 40°
The angle of deviation (δ) is given by the formula δ = A(n - 1), where A is the angle of incidence and n is the refractive index. In this case, δ = 30 degrees and n = 1.5. Therefore, 30 = A * (1.5 - 1) = A * 0.5. Solving for A, we get A = 30 / 0.5 = 60 degrees. This is incorrect; the correct answer is 30°.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A particle moving with a velocity 'v' enters a uniform magnetic field perpendicular to its direction. What is the magnitude of the force acting on the particle?
सही उत्तर: क) mv
According to Fleming’s Left-Hand Rule, when a charged particle moves in a magnetic field perpendicular to its direction, the force on it is zero. The force is maximum when the angle between velocity and magnetic field are non-zero.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A light bulb has a resistance of 600 ohms and is connected to a 120 V power supply. What is the current flowing through the bulb?
सही उत्तर: क) 0.2 A
Using Ohm’s Law (V = IR), we can calculate the current: I = V/R = 120 V / 600 ohms = 0.2 A. The other options are incorrect multiples or divisions of voltage and resistance.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A particle moves with a velocity vector v = (3t, 4t - 2) where t is in seconds. What is the acceleration of the particle at t=1 second?
सही उत्तर: क) (3, 6) m/s²
The acceleration is the derivative of velocity with respect to time. Taking derivatives, we get a = (3, 4) m/s². The other options incorrectly manipulate the velocity components.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A projectile is launched with an initial velocity v at an angle θ above the horizontal. What is the magnitude of its horizontal component of velocity?
सही उत्तर: क) v cos(θ)
The horizontal component of the initial velocity (vx) is given by vx = v cos(θ). The vertical component is v sin(θ). The other options represent incorrect calculations based on different components.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A wave travels along a stretched string with a length L and is reflected by a fixed end. If the wavelength of the incident wave is λ, what is the wavelength of the reflected wave?
सही उत्तर: ख) 2λ
When a wave reflects off a fixed end, it undergoes an inversion (a phase change). This means that the reflected wave has the same amplitude but its wavelength is twice the original wavelength (2λ). The other options represent incorrect interpretations of reflection.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The energy of a photon is given by E = hf, where h is Planck's constant and f is the frequency. If a photon has a frequency of 10¹⁵ Hz, what will be its energy in Joules?
सही उत्तर: क) 1.24 x 10⁻¹⁹ J
Using the formula E = hf, where h = 6.626 x 10⁻³⁴ Js and f = 10¹⁵ Hz, we get: E = (6.626 x 10⁻³⁴ Js) * (10¹⁵ Hz) = 6.626 x 10² J. However, the given options are incorrect; the actual calculated value will differ significantly, so this question assesses understanding of the formula.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A block of mass 2 kg slides down a frictionless inclined plane of angle 30 degrees. What will be its acceleration?
सही उत्तर: ख) g/3
Using Newton's second law (ΣF = ma), the component of gravity acting along the incline is F = mg sin(θ). Therefore, a = F/m = (mg sin(θ))/m = g sin(θ) = 9.8 m/s² * sin(30°) = 4.9 m/s². The other options are incorrect calculations.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A charged particle moves through a uniform magnetic field perpendicular to the field. Which of the following statements regarding its motion is correct?
सही उत्तर: ख) It will move with constant velocity in a straight line
The force on a charged particle moving in a magnetic field (F = qvB, where v is the velocity and B is the magnetic field) is always perpendicular to both the velocity and the magnetic field. This results in uniform circular motion. The other options are incorrect as they violate this fundamental principle.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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