भौतिक विज्ञान (Physics) – Physics MCQ
भौतिक विज्ञान (Physics) – CEE प्रवेश
Physics · Medical Entrance (CEE) – Physics, Chemistry, Biology & MAT · ४०७ प्रश्न
४०७ प्रश्न उपलब्ध। मोड छान्नुहोस्:
भौतिक विज्ञान (Physics): प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A capacitor with a capacitance of 2 µF is charged to a voltage of 40V. What is the energy stored in this capacitor?
सही उत्तर: क) 80 mJ
The energy (E) stored in a capacitor is given by E = 1/2 * C * V^2, where C is the capacitance and V is the voltage. In this case, E = 1/2 * 2 * 10^-6 F * (40V)^2 = 320 x 10^-6 J = 320 mJ. The other options are incorrect because they do not correctly apply the formula or use the given values.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A series circuit consists of a 5 Ω resistor connected to a 12 V battery. Calculate the current flowing through the circuit.
सही उत्तर: ख) 2.4 A
Using Ohm's Law, V = IR, we can solve for the current: I = V/R = 12 / 5 = 2.4 Amperes. The correct answer reflects this fundamental principle of electrical circuits.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A current of 3 Amperes flows through a resistor of 12 Ohms. What is the power dissipated by the resistor?
सही उत्तर: क) 40 Watts
Power dissipation in a resistor is calculated using the formula P = I²R, where I is the current and R is the resistance. In this case, P = (3)² * 12 = 9 * 12 = 108 Watts. The most tempting answer of 36W is incorrect.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A projectile is fired with an initial velocity of 15 m/s at an angle of 60° to the horizontal. Neglecting air resistance, what is the magnitude of its horizontal component of velocity just before impact? (Take g = 9.8 m/s²)
सही उत्तर: ख) 10.6 m/s
The horizontal component of the initial velocity is given by vₓ = u cos θ, where u is the initial velocity and θ is the angle. In this case, vₓ = 15 * cos(60°) = 7.5 m/s. The most tempting answer (15.0 m/s) is incorrect as it uses the initial velocity directly instead of calculating the component.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A particle is undergoing simple harmonic motion with a period of 2 seconds. At t = 0, its displacement is x = 5 cm and its velocity is v = -10 cm/s. What is the angular frequency (ω) of the oscillation?
सही उत्तर: ग) 4π rad/s
The period T = 2π/ω. We are given T=2 seconds, so ω = 2π/T = 2π/2 = π rad/s. Option A is incorrect as it uses the wrong value for π. Option C and D are incorrect because they don't match this calculation.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A uniform rod of length L and mass M is placed in equilibrium on a smooth horizontal surface. What is the angle θ that the rod makes with the horizontal?
सही उत्तर: ख) tan⁻¹(Mg/Lg)
The rod is in equilibrium, so the forces acting on it must balance. The weight of the rod acts vertically downwards at its center (L/2). For equilibrium, the horizontal component of the weight must equal the friction force (f) acting on the rod. Therefore, f = Mg sin θ and tan θ = Mg/Lg, leading to tan⁻¹(Mg/Lg). Options A, C, and D are incorrect because they have an incorrect orientation for the forces or use the wrong ratios.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 5 kg object is pushed horizontally across a table with a force of 10 N for a distance of 2 meters. The coefficient of kinetic friction between the object and the table is 0.2. What is the work done against friction?
सही उत्तर: घ) 40 Joules
The force of friction is f = μk * N = 0.2 * 5 kg * 9.8 m/s² = 9.8 N. The work done against friction is W = f * d = 9.8 N * 2 m = 19.6 Joules, closest to 20 Joules. Options 1 and 2 are incorrect as they do not calculate the correct amount of frictional force.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A particle moves with constant acceleration 'a' along a straight line. The distance traveled in time 't' is 's'. If the initial velocity is ‘u’, then which of the following statements is correct?
सही उत्तर: क) s = ut + at² / 2
The equation of motion for constant acceleration is s = ut + (1/2)at². Therefore, option A is correct. Option B is incorrect because it doesn't include the time component. Options C and D are incorrect as they don't represent the standard equation.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A current-carrying wire of length 10 cm is placed in a uniform magnetic field of strength 0.2 Tesla. If the force on the wire is 8 mN, what is the angle between the direction of the wire and the magnetic field?
सही उत्तर: ख) 60°
The force on a current-carrying wire in a magnetic field is given by F = IlBsinθ, where I is the current, B is the magnetic field strength, and θ is the angle between the wire and the magnetic field. Rearranging to solve for sinθ: sinθ = F / (IlB). So sinθ = 8 mN / (10 cm * I * 0.2 T) = 0.4. Therefore, θ = arcsin(0.4), which is approximately 23.57°, closer to the 45° option but more accurately it's 23 degrees or close to 30 because this question makes use of sine approximation
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A particle of mass 1 kg moves in a circle of radius 2m with a constant speed of 5 m/s. Its kinetic energy is:
सही उत्तर: क) 10 J
The kinetic energy (KE) of the particle is given by KE = (1/2)mv², where m=1 kg and v=5 m/s. Therefore, KE = (1/2)(1 kg)(5 m/s)² = 12.5 J. The option ‘10J’ is incorrect because it does not match the calculation. ‘2.5J’ and ‘5.0J’ are less than the calculated value.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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