मेडिकल प्रवेश (CEE) – Physics, Chemistry, Zoology, Botany, MAT
मेडिकल प्रवेश (CEE) – Physics, Chemistry, Zoology, Botany, MAT
Medical Entrance (CEE) – Physics, Chemistry, Biology & MAT · २,०३९ प्रश्न
२,०३९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
CEE प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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In simple harmonic motion, the speed of the particle is maximum at:
सही उत्तर: घ) The mean position
v = ω√(A² − x²) is maximum at x = 0. At the extreme positions speed is zero but acceleration is maximum.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In simple harmonic motion, the acceleration of the particle is:
सही उत्तर: ग) Proportional to displacement and directed towards the mean position
SHM is defined by a = −ω²x: magnitude proportional to displacement, direction towards the mean position. The minus sign is what makes the motion restoring.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A solid sphere, a hollow sphere, a ring and a disc of the same mass and radius roll without slipping down the same incline from rest. Which reaches the bottom first?
सही उत्तर: ख) Solid sphere
Acceleration a = g sinθ/(1 + I/MR²); the solid sphere has the smallest I/MR² (2/5), so it is fastest. The ring (I/MR² = 1) is slowest.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Torque acting on a body is equal to the rate of change of its:
सही उत्तर: क) Angular momentum
τ = dL/dt is the rotational analogue of F = dp/dt. Rate of change of linear momentum gives force, not torque.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The moment of inertia of a uniform circular disc of mass M and radius R about an axis through its centre and perpendicular to its plane is:
सही उत्तर: घ) MR²/2
For a disc, I = MR²/2. MR² is for a thin ring, where all the mass is at distance R.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Kepler's second law (law of areas) is a consequence of the conservation of:
सही उत्तर: ग) Angular momentum
Gravity is a central force, so it exerts no torque about the Sun and the planet's angular momentum is constant; this makes areal velocity constant. Hence planets move faster near perihelion.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The relation between escape velocity (vₑ) and orbital velocity (v₀) of a satellite close to the Earth's surface is:
सही उत्तर: ख) vₑ = √2 v₀
v₀ = √(gR) and vₑ = √(2gR), so vₑ = √2 v₀. Hence increasing a near-surface satellite's speed by about 41% would let it escape.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The acceleration due to gravity at the centre of the Earth is:
सही उत्तर: क) Zero
Inside the Earth g' = g(1 − d/R), which becomes zero at d = R. g is maximum at the surface, not at the centre.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The acceleration due to gravity at a height equal to the radius of the Earth (R) above its surface is:
सही उत्तर: घ) g/4
g' = g R²/(R + h)² = g R²/(2R)² = g/4. g/2 is a common mistake from assuming linear variation with distance.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The escape velocity of a body from the Earth does NOT depend on:
सही उत्तर: ग) The mass of the body
vₑ = √(2GM/R) contains only the planet's mass and radius, not the mass of the escaping body. A heavier body needs more energy but the same speed.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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