चिकित्सा शिक्षा आयोग (CEE) आयुर्वेद र होमियोप्याथी (BAMS) तयारी
चिकित्सा शिक्षा आयोग (CEE) – आयुर्वेद र होमियोप्याथी (BAMS)
BAMS Entrance · Medical Education Commission – CEE
२,०३९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
MBBS/BDS/Nursing प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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The term ‘chloroplast’ refers to: (a) The cellular structure responsible for protein synthesis. (b) The organelle where photosynthesis takes place. (c) The pigment that absorbs light energy in plants. (d) A type of cell division occurring in plant tissues.
सही उत्तर: ख) (b) The organelle where photosynthesis takes place.
The chloroplast is the specialized organelle within plant cells where photosynthesis occurs. Option (a) describes ribosomes, (c) refers to chlorophyll, and (d) describes mitosis.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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4.8 g of magnesium reacts completely with excess hydrochloric acid (Mg + 2HCl → MgCl₂ + H₂) to produce chlorine gas. The volume of chlorine produced at S.T.P. is:
सही उत्तर: ख) 22.4 L
First, calculate the moles of magnesium: 4.8 g / 24.3 g/mol = 0.2 mol. Then, use the stoichiometry of the reaction (1 mol Mg produces 1 mol Cl₂): 0.2 mol Mg produces 0.2 mol Cl₂. Finally, convert the moles of chlorine to volume at S.T.P. using the molar volume of a gas (22.4 L/mol).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A satellite is revolving around Earth at a height of 1600 km. Its orbital velocity is 7.5 km/s. What is the gravitational acceleration due to Earth at this altitude? (G = 6.674 × 10⁻¹¹ Nm²/kg², M_Earth = 5.972 × 10²⁴ kg, R_Earth = 6371 km)
सही उत्तर: ग) 11.2 m/s²
The orbital velocity is given by v = √(g * R_Earth), where g is the gravitational acceleration and R_Earth is the radius of Earth (6371 km). Solving for g, we get g = v²/R_Earth = (7.5 km/s)² / (6371 km) = 56.25 / 6371 ≈ 0.0088 m/s². Converting to more familiar units and using the provided values, this approaches close to 10.1m/s².
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A particle moves with constant acceleration along a straight line. At time t₁ = 2 s, its velocity is 6 m/s and at time t₂ = 5 s, its velocity is 12 m/s. What is the acceleration of the particle? (v = u + at)
सही उत्तर: ख) 4 m/s²
Using the equation v = u + at, we can solve for a. The change in velocity is 12 m/s - 6 m/s = 6 m/s, which occurred over a time interval of t₂ - t₁ = 5 s - 2 s = 3 s. Therefore, acceleration (a) = (Change in Velocity) / (Time Interval) = 6 m/s / 3 s = 2 m/s². This is not one of the options – it’s important to note that this calculation assumes constant acceleration.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A mass of 5 kg is attached to a spring with a spring constant k = 100 N/m. The mass is displaced from its equilibrium position by 0.2 meters and released. What will be the angular frequency of the resulting oscillation? (ω = √(k/m))
सही उत्तर: घ) 20 rad/s
The angular frequency (ω) is calculated using the formula ω = √(k/m), where k is the spring constant (100 N/m) and m is the mass (5 kg). Plugging in these values, we get ω = √((100 N/m)/5 kg) = √20 rad²/s = 4.47 rad/s. The correct answer closest to 20 rad/s is a mistake - it’s vital to recognize that the given problem asks for angular frequency.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A uniform wire of length 1 meter and cross-sectional area 1 mm² is stretched so that its length becomes 2 meters. Assuming the elastic modulus of the wire is 8 x 10⁹ N/m², what is the stress applied to the wire? (Use Young's Modulus formula: Stress = Elasticity * Strain)
सही उत्तर: ख) 8 x 10^9 N/m²
First, calculate the strain: Strain = (Change in Length) / (Original Length) = 2 m / 1 m = 2. Then, Stress = Young’s Modulus * Strain = (8 x 10⁹ N/m²) * 2 = 16 x 10⁹ N/m². The option ‘4 x 10^9 N/m²’ is too low because it doesn't consider the linear relationship between stress and strain.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The normality of a solution containing 2 g of NaOH in 500 ml of water is:
सही उत्तर: ख) 0.5 N
Normality is defined as the number of equivalents per liter of solution. NaOH dissociates into one ion of Na⁺ and one ion of OH⁻, so it has two equivalents per mole. Therefore, the normality is 2.0 N. The most tempting incorrect option, 1.0 N, comes from only considering the moles of NaOH without accounting for its dissociation.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a certain code, A=1, B=2, C=3, and so on. What is the numerical value of the word 'CAT'?
सही उत्तर: क) 123
This is simple letter-to-number substitution. 'C' = 3, 'A' = 1, and 'T' = 20. Therefore, CAT = 3120.”}],
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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If a rectangle has a length of 12 cm and a width of 8 cm, what is the area of the rectangle?
सही उत्तर: क) 96 sq cm
The area of a rectangle is calculated by multiplying its length and width. Therefore, the area is 12 cm * 8 cm = 96 square centimeters.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A group of people are seated in a row. A certain person is sitting next to two other people. How many people could be in the group?
सही उत्तर: क) 3
The correct answer is 4. If one person is sitting next to two others, they must form a group of at least three people. Any additional people can then join this group; thus forming groups up to six people as well.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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