चिकित्सा शिक्षा आयोग (CEE) बीडीएस प्रवेश परीक्षा तयारी
चिकित्सा शिक्षा आयोग (CEE) – बीडीएस प्रवेश परीक्षा
CEE – BDS Entrance · Medical Education Commission – CEE
२,०३९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
MBBS/BDS/Nursing प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A charged particle enters a uniform magnetic field perpendicularly to the field. If the magnitude of the charge is 'q' and the velocity is 'v', what is the magnitude of the force experienced by the particle?
सही उत्तर: क) A) qv
The correct answer is (A). According to the Lorentz Force Law, the magnetic force on a charged particle moving in a magnetic field is F = q(v x B), where 'x' denotes the cross product. When v and B are perpendicular, the magnitude of the force is F = qv.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A uniform disk of mass M and radius R rolls without slipping down an inclined plane of angle θ. What is the magnitude of its angular acceleration?
सही उत्तर: ख) B) gR / (MR)
The correct answer is (B). Using Newton's second law for rotational motion, τ = Iα, where τ is the torque and α is the angular acceleration. The torque is τ = M * g* sin(θ), and the moment of inertia for a uniform disk rotating about its center is I = 1/2 * MR². Solving for alpha gives α = (gsin(θ)) / (MR) – this option provides the correct numerical value.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A projectile is launched with an initial velocity v₀ at an angle θ with respect to the horizontal. If air resistance is negligible, what is the trajectory of the projectile described by?
सही उत्तर: क) A) A parabola
The correct answer is (A). In the absence of air resistance, the only force acting on the projectile is gravity. This results in a parabolic trajectory, as described by classical mechanics. Options B, C and D are incorrect because they represent scenarios with additional forces or movement patterns that do not apply in this idealized situation.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A sound wave has a frequency of 440 Hz and an amplitude of 0.1 m. What is the wavelength of the sound wave if its speed in air is 340 m/s?
सही उत्तर: ग) 0.9 m
The relationship between speed (v), frequency (f), and wavelength (λ) of a wave is v = fλ. Rearranging to solve for λ: λ = v/f = 340m/s / 440 Hz ≈ 0.77 m. Option 2 (1.1m) is the closest plausible value.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The force required to drag a block across a rough horizontal surface is given by F = μN, where μ is the coefficient of friction and N is the normal reaction. If the frictional force is 10 N and the normal reaction is 20 N, what is the coefficient of friction?
सही उत्तर: घ) 5
We have F = μN. Solving for μ: μ = F/N = 10N / 20N = 0.5. Options 0.5, 1, 2, and 5 are all plausible as they represent possible values of a coefficient of friction; however, only 0.5 is the correct calculation.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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एक आयताकार क्षेत्रको लांस क्रमशः 12 सेमी र 9 सेमी हुन्। यदि यसको क्षेत्रफल 108 वर्ग सेमी छ भने, हाइपरटोनल दूरी (perimeter) कस्तो हुन्छ?
सही उत्तर: ग) 72 सेमी
The area of a rectangle is length × width. Here, length = 12 cm and width = 9 cm, but the actual area is stated to be 108 sq cm. We calculate the perimeter as 2(length + width) = 2(12+9) = 2(21) = 42 cm. The question has an inconsistency (given area of 108), and asks for *hypertonal distance* which may be a misinterpretation - we assume they meant perimeter.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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If 'RED' is coded as 'EBR', how is 'BLUE' coded?
सही उत्तर: क) EBUL
The code involves reversing the letters of each word. ‘RED’ reversed is ‘DER’, but in this case, it’s stated ‘EBR’. Applying this to ‘BLUE’, we get ‘ELBU’.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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'SUN' लाईको कोड 'NUS' भन्दा विपरीत हो। 'RAIN' लाईको कोड कस्तो हुन्छ?
सही उत्तर: ख) NAIR
The coding involves reversing the letters of the original word. ‘SUN’ reversed is ‘NUS’. Applying this to ‘RAIN’, we get ‘NAIR’.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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यदि 'COMPUTER' लाईको कोड 'PRTEOMU' भन्दा विपरीत हो भने 'EDUCATION' लाईको कोड कस्तो हुन्छ?
सही उत्तर: घ) DOITECNU
The code reverses the letters of the word. ‘COMPUTER’ reversed is ‘PRTEOMU’. Therefore, applying this to ‘EDUCATION’, we get ‘DOTCIENU’.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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'LEVEL' is written as 'VELEL'. How is 'TRAIN' written in that code?
सही उत्तर: क) TRINA
The code involves rearranging the letters of the original word. In this case, the letters are rearranged from left to right, but with the second letter moved to the beginning. Applying this to ‘TRAIN’, we get TRINA.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।