चिकित्सा शिक्षा आयोग (CEE) बीडीएस प्रवेश परीक्षा तयारी
चिकित्सा शिक्षा आयोग (CEE) – बीडीएस प्रवेश परीक्षा
CEE – BDS Entrance · Medical Education Commission – CEE
२,०३९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
MBBS/BDS/Nursing प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A man has two sons. The first son is twice as old as the second son. The second son is three years younger than the first son. How old is the youngest son?
सही उत्तर: क) 3
Let 'x' be the age of the youngest son. The first son is 2x, and the second son is 2x - 3. We can set up an equation: 2x - 3 = x. Solving for x gives x=3. The most misleading answer is 6 because it's a multiple of '2x'.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Limulus polyphemus (the ‘living fossil’) is a highly significant species in marine biology. To which phylum does it primarily belong?
सही उत्तर: क) Mollusca
Limulus is a member of the Phylum Arthropoda, more specifically within the subphylum Chelicerata, and is classified as a 'living fossil' due to its ancient lineage resembling early arthropods – particularly horseshoe crabs.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A sequence has terms: 3, 6, 15, 30, 63, ?
सही उत्तर: क) 84
The sequence follows a pattern where each term is roughly double the previous one and related to squares. Specifically, it's 3(1), 3(2), 3(5), 3(10), 3(21). The differences between consecutive terms increase: 3, 9, 5, 11... This leads us to the next term as 3 * (21 + 8) = 3*29=87, but this isn't in our options. Reconsidering, another pattern is that each number can be written as n^2 + n. So we have: 1^2+1=2, 2^2+2=6, 3^2+3=12 (not correct), 4^2+4 = 20(incorrect). The formula seems inaccurate because of the difference in terms.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Which specific cellular structure is directly responsible for the formation of pollen grains in flowering plants?
सही उत्तर: ग) c) The microsporangium (sporophyte), where meiosis occurs to produce haploid spores that develop into pollen grains.
The microsporangium is the site of pollen grain development through meiosis. Options (a), (b) and (d) describe different cellular functions unrelated to pollen formation.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The presence of cyanobacteria within the root nodules of leguminous plants contributes to nitrogen fixation by:
सही उत्तर: ख) b) Reducing nitrate ions to nitrite ions, which are then converted to ammonia.
Option (b) accurately describes the mechanism of nitrogen fixation within root nodules. Cyanobacteria convert nitrate into nitrite, which is then reduced to ammonia – a usable form for plants. Options (a) is a simplification; (c) describes nutrient absorption, and (d) is unrelated.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The term ‘heteroblasty’ refers to:
सही उत्तर: ख) b) The differentiation of plant parts into different types of tissues at various stages of development, resulting in distinct morphologies.
Option (b) is the correct definition of heteroblasty. It describes the diverse developmental pathways plants exhibit, resulting in different forms for leaves, flowers, etc. Options (a) refers to holoblastic development, (c) describes vegetative propagation, and (d) pertains to flower colour changes which are a related but distinct process.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The primary function of stomata in plant leaves is: (a) Absorption of water from the soil (b) Exchange of gases (carbon dioxide and oxygen) (c) Translocation of sugars throughout the plant (d) Photosynthesis only occurring at night
सही उत्तर: ख) (b) Exchange of gases (carbon dioxide and oxygen)
Option (b) is correct as stomata are crucial for regulating gas exchange – taking in carbon dioxide for photosynthesis and releasing oxygen. The other options describe different processes like water uptake via roots, sugar transport within the plant's vascular system, or a single-process function.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 200 gram mass is attached to a vertical spring with a spring constant k = 50 N/m. If the mass is displaced downward by 10 cm and released, what will be its angular frequency (ω) of oscillation?
सही उत्तर: ग) 8.6 rad/s
The angular frequency is given by ω = √(k/m), where k is the spring constant and m is the mass. Substituting the values, we get ω = √(50 N/m / 0.2 kg) = √250 rad²/s ≈ 15.8 rad/s. The closest option is 8.6 rad/s, but it's crucial to understand how angular frequency relates to mass and spring constant.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A uniform rod of length L and mass M is placed on a smooth horizontal surface. A force F is applied perpendicular to the rod at its center. What is the magnitude of the acceleration of the rod?
सही उत्तर: क) (F/M)
Because the surface is smooth, there's no friction. Newton's second law states F = Ma, so acceleration a = F/M. The other options are incorrect because they involve friction or misinterpret the application of Newton’s laws.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A particle of mass m is attached to a fixed point by a string of length l and moves in a horizontal circle of radius r at a speed v. What is the magnitude of the tension in the string?
सही उत्तर: घ) 2ml
The centripetal force required to keep the particle moving in a circular path is provided by the tension in the string, given by F = mv²/r. Therefore, the magnitude of the tension is mvl/r which simplifies to ml. Options 2 and 4 are incorrect as they have extraneous terms or incorrectly state the quantity.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।