चिकित्सा शिक्षा आयोग (CEE) बीडीएस प्रवेश परीक्षा तयारी
चिकित्सा शिक्षा आयोग (CEE) – बीडीएस प्रवेश परीक्षा
CEE – BDS Entrance · Medical Education Commission – CEE
२,०३९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
MBBS/BDS/Nursing प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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Which of the following plant hormones is a gas and plays a crucial role in the climacteric ripening phase of fruits?
सही उत्तर: ग) C) Ethylene
Option C (Ethylene) is correct – ethylene is a gaseous hormone responsible for fruit ripening. Auxin and abscisic acid are generally associated with growth regulation and dormancy, while cytokinin primarily affects cell division.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Gibberellins are commonly used in barley cultivation to promote grain growth. What is the primary physiological effect of these hormones on the barley grains?
सही उत्तर: ख) B) Stimulation of stem elongation
Option B (Stimulation of stem elongation) is correct as gibberellins are well-known for their role in promoting stem growth. Options A, C, and D represent other established functions of plant hormones like florigen, ethylene, or abscisic acid respectively, which aren't the primary effect related to barley grain development.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The reaction of potassium permanganate (KMnO₄) with oxalic acid (H₂C₂O₄) in acidic solution produces manganese ions (Mn²⁺). What is the oxidation state of manganese in Mn²⁺?
सही उत्तर: क) +2
The oxidation state of manganese in Mn²⁺ is +2. Manganese typically exists in various oxidation states, and in this reaction, it loses two electrons to become Mn²⁺.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Which of the following reagents would be most suitable for oxidizing ethanol (CH₃CH₂OH) to acetaldehyde (CH₃CHO)?
सही उत्तर: ग) KI
Chromium(VI) oxide (H₂CrO₄) is a strong oxidizing agent commonly used in organic chemistry for converting primary alcohols to aldehydes. The other options are reducing agents or catalysts, not oxidants capable of selectively transforming ethanol.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The decomposition of N₂O₅ at 44°C yields NO₂ and O₂O₅ decomposes at 44°C yields NO₂ and O₂. When 50g of N₂O₅ is heated to 44°C, 68g of NO₂ are produced. What mass of O₂ is also produced?
सही उत्तर: ख) 34g
This is a stoichiometry problem based on the law of conservation of mass. The balanced equation for this reaction is N₂O₅ → 2NO₂ + O₂. Using the given masses of N₂O₅ and NO₂, we can calculate the moles and subsequently the moles of O₂ produced, then convert to grams.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Which of the following correctly describes the process of spermatogenesis? (a) The formation of mature female gametes from diploid cells. (b) The production of haploid male gametes through meiosis and subsequent differentiation. (c) A continuous cycle of cell division without genetic recombination. (d) The fusion of sperm and egg to initiate development.
सही उत्तर: ख) A process involving mitosis only, leading to increased cell numbers.
Option (b) accurately describes spermatogenesis – the creation of haploid male gametes (sperm) through meiosis. It's a key process distinguishing male and female reproductive systems. Options (a), (c), and (d) describe either oogenesis or fertilization/general cellular processes respectively.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Find the next letter in the sequence: B, D, G, J, O, U, ?
सही उत्तर: ग) V
The pattern is based on adding increasing consecutive numbers to the position of each letter in the alphabet. B (+2)=D, D(+3) =G, G(+3) =J, J(+4) =O, O(+4) =U, U(+5)=V
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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If ‘A’ is North, ‘B’ is East, ‘C’ is South and ‘D’ is West, what does ‘AC’ represent?
सही उत्तर: ख) Southeast
‘A’ is North and ‘C’ is South. Therefore, ‘AC’ represents Southeast.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The refractive index of glass is 1.5 at a particular wavelength. If a ray of light travels from air into this glass with an angle of incidence of 30°, what will be the angle of refraction?
सही उत्तर: क) 30°
Using Snell's Law, we have n₁sinθ₁ = n₂sinθ₂, where n₁ and n₂ are the refractive indices of air (1) and glass (1.5), respectively, and θ₁ is the angle of incidence (30°) and θ₂ is the angle of refraction. Therefore, 1 * sin(30°) = 1.5 * sin(θ₂). Thus, sin(θ₂) = sin(30°) / 1.5 = 0.5/1.5 ≈ 0.333. Therefore, θ₂= arcsin(0.333) which is approximately 19.47°, but this doesn't match any of the options. A more accurate calculation considering wave refraction will result in a closer value to none of provided options. The nearest correct answer would be 45°.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A liquid flows through a horizontal pipe of length L with a decreasing cross-sectional area. If the pressure drop in the pipe is ΔP and the viscosity of the fluid is η, what is the velocity (v) of the fluid?
सही उत्तर: क) ΔP/ηL
According to Bernoulli's principle and Poiseuille's Law, the pressure drop in a pipe is related to the velocity of flow. Specifically, for laminar flow: ΔP = η * (v²/A), where A is the cross-sectional area. Rearranging this equation gives v = sqrt((ΔP*A)/η).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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