चिकित्सा शिक्षा आयोग (CEE) बीएस्सी नर्सिङ र बीएनएस प्रवेश तयारी
चिकित्सा शिक्षा आयोग (CEE) – बीएस्सी नर्सिङ र बीएनएस प्रवेश
B.Sc. Nursing & BNS Entrance · Medical Education Commission – CEE
२,०३९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
MBBS/BDS/Nursing प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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What is the primary reason for using argon gas instead of air in incandescent light bulbs?
सही उत्तर: ख) Argon is less reactive than air
Argon is chemically inert and does not readily react with the filament material (typically tungsten), preventing its oxidation and ensuring longer bulb life. Air contains oxygen, which would rapidly oxidize the tungsten filament at high temperatures.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Which of the following statements correctly describes the relationship between electronegativity and bond polarity in a polar covalent bond?
सही उत्तर: ग) Larger electronegativity difference results in a longer, stronger bond
In polar covalent bonds, the greater the difference in electronegativity between two atoms, the more unevenly electron density is distributed, creating a dipole moment and thus polarity. Options 1, 2 and 3 are incorrect as they describe weaker or shorter non-polar bonds.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The molar mass of carbon dioxide (CO₂) is approximately 44 g/mol. What mass of CO₂ is produced when 1 mole of propane (C₃H₈) undergoes complete combustion?
सही उत्तर: क) 18g
Combustion of one mole of propane produces two moles of carbon dioxide. The molar mass of CO₂ is 44 g/mol, so two moles will weigh 2 * 44 = 88 grams. Options 18g, 36g and 44g are incorrect as they do not account for the stoichiometry of the reaction.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The partial pressure of nitrogen (N₂) in a closed container at 25°C is 0.75 atm and the partial pressure of oxygen (O₂) is 1.0 atm. What is the total pressure of the gas mixture in the container?
सही उत्तर: क) 1.75 atm
According to Dalton’s Law of Partial Pressures, the total pressure is the sum of the partial pressures of all gases present in a mixture. Therefore, Total Pressure = P(N₂) + P(O₂) = 0.75 atm + 1.0 atm = 1.75 atm.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Five friends, A, B, C, D, and E, are seated in a row facing north. C is sitting in the middle, and B is sitting at the extreme right end of the row. How many seats are there between A and E?
सही उत्तर: घ) 1
Since C is in the middle (the 3rd position), and B is at the extreme right (the 6th position), there are 5 people total. The arrangement is _ _ C _ _ B. Therefore, A and E must be in positions 1 and 4 respectively with three seats between them. The tempting answer '1' assumes A and E are directly adjacent, which isn’t the case.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Consider the set of digits {1, 2, 3, 4, 5}. How many distinct 3-digit numbers can be formed using these digits without repetition?
सही उत्तर: ख) 24
This is a permutation problem. We need to find the number of ways to arrange 3 distinct digits chosen from a set of 5, which is calculated as P(5,3) = 5! / (3! * 2!) = (5 * 4 * 3) / (3 * 2 * 1) = 10. This calculation is incorrect, we need to select three distinct digits from five and arrange them in a particular order. The number of ways to do this is 5P3= 5*4*3=60. But the correct answer should be 60.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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What is the next term in the series: 1, 8, 27, 64, ?
सही उत्तर: घ) 169
The series consists of cubes of natural numbers (1^3=1, 2^3=8, 3^3 = 27, 4^3=64. The next term is 5^3=125.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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If ‘RED’ is coded as ‘WLO’, then what is the code for ‘BLUE’?
सही उत्तर: ख) GDS
The coding appears to be shifting each letter forward by one position in the alphabet: R-> W, E -> L, D -> O. Applying this pattern to BLUE gives B-> G , L ->D, U -> S, and E ->D.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The phenomenon of apical dominance, where the main stem grows vigorously while lateral branches remain short, is primarily controlled by: (a) Ethylene produced by roots. (b) Cytokinin produced in shoot tips. (c) Gibberellin synthesized in fruits. (d) Auxin concentrated in root caps.
सही उत्तर: ख) Cytokinin produced in shoot tips.
Option (b) is correct; Cytokinins are synthesized at the tips of shoots and promote cell division and growth, suppressing lateral bud development (apical dominance). The other options represent different plant hormones with distinct roles.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Which of the following correctly describes the role of guard cells in regulating stomatal aperture? (a) They open when carbon dioxide concentration increases. (b) They close when water potential decreases. (c) They respond to changes in light intensity and CO2 levels. (d) They are controlled solely by hormonal signals like abscisic acid.
सही उत्तर: घ) They are controlled solely by hormonal signals like abscisic acid.
Option (c) is correct; guard cells open in response to increased CO2 or light and close when water potential drops (due to water loss). Options (a), (b), and (d) are incorrect depictions of stomatal control mechanisms.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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