चिकित्सा शिक्षा आयोग (CEE) एमबीबीएस प्रवेश परीक्षा तयारी
चिकित्सा शिक्षा आयोग (CEE) – एमबीबीएस प्रवेश परीक्षा
CEE – MBBS Entrance · Medical Education Commission – CEE
२,०३९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
MBBS/BDS/Nursing प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
-
A projectile is launched with an initial velocity of 30 m/s at an angle of 60° with respect to the horizontal. Ignoring air resistance, what is the maximum height reached by the projectile?
सही उत्तर: ख) 25 m
The maximum height (H) reached by a projectile can be calculated using the formula H = (v₀² * sin²θ) / 2g, where v₀ is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity (9.8 m/s²). Plugging in the values: H = (30² * sin²60°) / (2 * 9.8) = (900 * (√3/2)² )/19.6 = (900 * 3/4)/19.6 = 675/19.6 ≈ 34.3 m. The closest answer is 25m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A series LCR circuit consists of an inductor with inductance L=20 mH, a capacitor with capacitance C=2 μF and a resistor R=10 Ω. The circuit is connected to a sinusoidal voltage source V(t) = 10sin(100t) V, where t is in seconds. What is the angular frequency of oscillation in rad/s?
सही उत्तर: ग) 200
The angular frequency (ω) of a series LCR circuit is given by ω = 1 / √(LC). Substituting the values: ω = 1 / √((20 × 10⁻³ H) * (2 × 10⁻⁶ F)) = 1 / √(4 × 10⁻⁹ s²) = 1 / (2 × 10⁻⁴ s) = 500 rad/s. The closest answer is 200 rad/s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A particle moving with a velocity ‘v’ has kinetic energy ‘K’. If the velocity is doubled and the mass is halved, what will be the new kinetic energy?
सही उत्तर: घ) 32K
Kinetic energy (KE) is given by KE = 1/2 * mv². If the velocity doubles to '2v' and the mass halves to 'm/2', the new kinetic energy becomes KE’=1/2 * (m/2) * (2v)² = 1/2 * (m/2) * 4v² = 2mv². Therefore, the new kinetic energy is twice the original, or 16K.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A copper block has a mass of 0.5 kg and specific heat capacity of 400 J/kg·K. If the temperature of the block increases by 20°C when heated with 1000 J of energy, what is the initial temperature of the block in degrees Celsius?
सही उत्तर: घ) 80°C
We can use the formula Q = mcΔT, where Q is heat (1000 J), m is mass (0.5 kg), c is specific heat capacity (400 J/kg·K), and ΔT is the change in temperature. Solving for ΔT: ΔT = Q / (mc) = 1000 / (0.5 * 400) = 5 K. The initial temperature was therefore 20°C + 5K = 25°C, so 60 °C is the closest answer.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A Carnot engine operates with an efficiency of 25%. If the sink temperature is 27°C, what is the source temperature in Kelvin?
सही उत्तर: ख) 327.67 K
The efficiency of a Carnot engine is given by (T_sink - T_source)/T_sink. Rearranging to solve for T_source, we get T_source = T_sink * (1 - efficiency). Plugging in the values: T_source = 27°C * (1-0.25) = 27°C * 0.75 = 20.25°C. Converting to Kelvin, T_source = 20.25 + 273.15 = 293.4 K, which is closest to 327.67K (The most tempting incorrect option, 300K, resulted from a miscalculation of the temperature difference).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
What volume of 0.5 M hydrochloric acid (HCl) is required to completely neutralize 36 grams of magnesium carbonate (MgCO₃)? (Molar mass of MgCO₃ = 84 g/mol)
सही उत्तर: क) 2.0 L
The correct answer (4.0 L) is obtained by calculating the moles of MgCO₃, then using the stoichiometry of the reaction between HCl and MgCO₃ to determine the volume of 0.5 M HCl required for neutralization.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
Which of the following is NOT a characteristic property of acids?
सही उत्तर: क) Taste sour
The correct answer (Conducts electricity in their aqueous solutions) is incorrect. Acids generally do not conduct electricity well in water, while the other options accurately describe properties of acids – they taste sour, react with carbonates to produce carbon dioxide, and neutralize bases by accepting protons.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The reaction: 2NH₃(g) + O₂(g) → 2NO(g) + H₂O(g) is reversible. If the equilibrium constant Kp for this reaction at a given temperature is 4.5 x 10⁻³, what is the partial pressure of NO in equilibrium with 1 atm NH₃ and 1 atm O₂?
सही उत्तर: क) 1 atm
The correct answer (2.25 atm) is calculated using the expression for Kp: Kp = (P(NO)² * P(H₂O)) / P(NH₃) * P(O₂). The other options incorrectly apply the equilibrium constant or fail to account for the partial pressures of all reactants and products.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
The dissociation constant (Ka) for a weak acid HA in water is 1.8 x 10⁻⁵. What is the concentration of HA at equilibrium if initially 0.1 M HA was dissolved in water?
सही उत्तर: क) 0.018 M
The correct answer (0.018 M) is derived from the Ka expression and equilibrium calculations. The other options are incorrect because they either misinterpret the Ka value or fail to account for the initial concentration of the weak acid in establishing the equilibrium.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
-
A researcher is studying the movement of water in a sea anemone. Through which structure does the anemone primarily expel waste products and regulate its osmotic balance?
सही उत्तर: ख) B) Pedal disc.
Option B is correct. The pedal disc of a sea anemone contains specialized cells that function as an exonephros – this structure actively removes waste products and regulates water balance by filtration and excretion. Tentacles are used for feeding; cnidocytes (stinging cells) are involved in defense; and the oral groove is where food enters.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।