चिकित्सा शिक्षा आयोग (CEE) एमबीबीएस प्रवेश परीक्षा तयारी
चिकित्सा शिक्षा आयोग (CEE) – एमबीबीएस प्रवेश परीक्षा
CEE – MBBS Entrance · Medical Education Commission – CEE
२,०३९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
MBBS/BDS/Nursing प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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Annual rings in tree trunks are formed due to variations in: (A) Root length (B) Stem diameter (C) Growth rate, influenced by seasonal changes in temperature and precipitation (D) Leaf size
सही उत्तर: ग) (C) Growth rate, influenced by seasonal changes in temperature and precipitation
Annual rings are created by the annual growth cycle of trees. The rapid growth during warmer months leads to a lighter-colored ring, while slower growth during colder months creates a darker ring. The tree’s diameter varies during this process.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In rice and wheat, pollen grains typically lose their viability within approximately: (A) 1-2 days (B) 7-14 days (C) 30-60 days (D) 90-120 days
सही उत्तर: ख) (B) 7-14 days
Pollen viability is significantly reduced after fertilization. Within a few days of successful pollination, the pollen grains lose their ability to germinate and fertilize ovules. The values are between one to two days.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Which of the following statements accurately describes the composition of the exine of a pollen grain? (A) Primarily cellulose and pectin (B) A complex mixture of proteins, lipids, and polysaccharides (C) Primarily sporopollenin, a highly resistant polymer (D) Mostly starch granules for energy storage
सही उत्तर: ग) (C) Primarily sporopollenin, a highly resistant polymer
The exine is the tough outer layer of a pollen grain. It’s primarily composed of sporopollenin, a complex polymer providing protection and resistance to degradation, making it exceptionally durable. Options (A) and (D) describe different components present in the inner layers.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The primary function of phloem tissue in plants is: (A) Support and transport of water and minerals (B) Transport of sugars produced during photosynthesis (C) Protection against herbivores and pathogens (D) Reproduction through seed formation
सही उत्तर: ख) (B) Transport of sugars produced during photosynthesis
Phloem is responsible for transporting organic compounds, primarily sucrose, throughout the plant. The other options describe functions of different tissue types like xylem or protective structures. Option (A) describes Xylem function.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A particle moves with a constant velocity in a magnetic field. Which of the following statements is true about the force experienced by the particle?
सही उत्तर: ख) The force is perpendicular to both velocity and magnetic field
According to the Lorentz Force Law, a charged particle moving in a magnetic field experiences a force that is always perpendicular to both its velocity and the magnetic field. This makes option 1 correct. The other options misrepresent the relationship between the force and these variables.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A uniform cube of side 'a' has a mass of 2 kg. What is its moment of inertia about an axis perpendicular to one face passing through the center of the cube?
सही उत्तर: ख) 5/6 ma²
The moment of inertia for a uniform cube rotating about an axis through its center and perpendicular to one face is (1/12)m(a^2). In our case, m=2kg and a=0.5m, therefore the Moment of Inertia = (1/12)*2*(0.5)^2 = 1/6 * (0.25) kg*m² = 1/6 ma². The other answers involve incorrect calculations using different moment of inertia formulas, like those for solids of revolution.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A stone is thrown vertically upwards with an initial velocity of 20 m/s from the top of a building of height 80 meters. What is the time taken for the stone to hit the ground?
सही उत्तर: ग) 4.5 s
We can use equations of motion. First, we find the time to reach maximum height (v = 0) using v = u + at, where v=0, u=20 m/s and a=-9.8 m/s². So t = 20/9.8 ≈ 2 s. Then, from the top of the building to the ground, the distance is given by h = ut + (1/2)at², where h=80m, u=20m/s and a=-9.8 m/s². Solving for t gives t = sqrt((-h)/(a)) =sqrt(-80 / 9.8) = 4.5 seconds. The other answers are either incorrect calculations of the time to reach maximum height or an incorrect use of the distance formula.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The kinetic energy of a particle moving with velocity v is given by KE = (1/2)mv². If the velocity is increased by 20% while its mass remains constant, what is the percentage increase in kinetic energy?
सही उत्तर: घ) 80
If the velocity increases by 20%, the new velocity will be 1.2v. The new kinetic energy KE' = (1/2)(m)(1.2v)² = (1/2)mv(1.44). Therefore, the ratio of KE’ to KE is 1.44, meaning the kinetic energy increased by 44%. This makes 40% the correct answer. Calculating the percentage increase involves (KE’ - KE)/KE * 100%, so ((1.44-1)*100%) = 44%. The other options were calculated with incorrect velocity changes.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A body is projected upwards with an initial velocity of 40 m/s. What is the maximum height reached by the body? (Take g = 9.8 m/s²)
सही उत्तर: ख) 73.5 m
The maximum height is reached when the final velocity becomes zero. Using the equation v² = u² + 2as, where v=0, u=40m/s, a=-9.8m/s², and s is the maximum height. Solving for s gives us (0)² = (40)² + 2(-9.8)s, so s = 84.6 m. The most tempting incorrect answer is 62.1m as this requires a different initial velocity to achieve that height.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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If a particle is moving with velocity v at an angle θ to the x-axis, what are the x and y components of its velocity?
सही उत्तर: क) x = v cosθ, y = v sinθ
The x and y components of a velocity vector are found using trigonometric functions. Specifically, the x-component is given by v * cos(θ) and the y-component is given by v * sin(θ). This represents breaking the velocity into its horizontal (x) and vertical (y) components.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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