चिकित्सा शिक्षा आयोग (CEE) एमबीबीएस प्रवेश परीक्षा तयारी
चिकित्सा शिक्षा आयोग (CEE) – एमबीबीएस प्रवेश परीक्षा
CEE – MBBS Entrance · Medical Education Commission – CEE
२,०३९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
MBBS/BDS/Nursing प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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The primary function of stomata in plant leaves is to regulate:
सही उत्तर: ख) Water loss through transpiration
Stomata are pores that control the exchange of gases, primarily facilitating transpiration (water loss) while allowing carbon dioxide intake for photosynthesis. The other options describe different plant functions.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The phenomenon of apical dominance, where a terminal bud suppresses the growth of lateral buds, is primarily controlled by which hormone?
सही उत्तर: ख) Cytokinin
Cytokinins are known to promote lateral bud development and counteract apical dominance. While auxin plays a role in overall plant growth, it's not the primary regulator of this specific phenomenon.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Which of the following structures primarily facilitates the movement of water and minerals from the roots to the stem and leaves in a plant?
सही उत्तर: क) Root hairs
Xylem vessels are specialized cells specifically designed for conducting water and minerals upwards. The other options – root hairs, phloem tubes, and the cuticle layer – have different primary functions within the plant.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 25.0 mL solution of a hydrochloric acid (HCl) requires 18.40 mL of 0.300 M sodium hydroxide (NaOH) for neutralization. What is the molarity of the HCl solution?
सही उत्तर: घ) 2.40 M
The number of moles of HCl equals the number of moles of NaOH (since they react 1:1). Calculate the molarity using the formula Molarity = moles / volume (in liters). The correct answer is derived by correctly applying the stoichiometry and calculating the final concentration.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Which of the following describes the relationship between ionic product (Ksp) and solubility of a sparingly soluble salt?
सही उत्तर: ख) Ksp decreases with increasing solubility
The solubility product, Ksp, represents the equilibrium constant for the dissolution of a sparingly soluble ionic compound. As more solute dissolves (increasing solubility), the ion concentrations increase, leading to a decrease in Ksp. This accurately reflects the thermodynamic relationship.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The decomposition of lead(II) iodide (PbI₂) is represented by the following balanced equation: 2PbI₂(s) → 2Pb(s) + I₂(s). If a sample of 10.0g PbI₂ decomposes completely, what mass of iodine (I₂) will be produced?
सही उत्तर: ख) 5.33 g
First, calculate the molar mass of PbI₂ (207.2 + 126.9 = 334.1g/mol). Then, use stoichiometry: 2 moles of PbI₂ produce 1 mole of I₂. Therefore, the required mass is calculated correctly based on the balanced equation.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The oxidation number of chromium (Cr) changes from +6 to +3 in the following chemical reaction: Cr₂O₉²⁻ + 8H⁺ → 2Cr³⁺ + 9H₂O. Which of the following correctly describes this change?
सही उत्तर: ग) It involves oxidation of chromium
In this reaction, chromium changes from Cr(VI) to Cr(III), representing a +6 to +3 oxidation state change. This exemplifies oxidation; the most plausible answer reflecting this change involves chromium being oxidized. The other options either misrepresent the overall process or focus on irrelevant details.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The length of a simple pendulum is increased by 20%. The new time period will be: (a) Increased by 20% (b) Decreased by 20% (c) Increased by 10% (d) Decreased by 10%
सही उत्तर: ख) Decreased by 20%
The time period (T) of a simple pendulum is given by T = 2π√(L/g), where L is the length and g is the acceleration due to gravity. If the length increases by 20%, the new length will be 1.2L. The new time period will then be T' = 2π√(1.2L/g) = 2π√1.2 * √(L/g) = √1.2 * (2π√(L/g)) = √1.2 * T, which is approximately a 20% increase.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A point charge +q is placed at the center of a spherical shell. The electric flux through the surface of the shell will be: (a) Zero (b) Equal to $rac{ ext{q}}{2}rac{1}{4 imes 10^9}$ N⋅m²/s (c) Equal to $rac{ ext{q}}{8 imes 10^9}$ N⋅m²/s (d) Infinite
सही उत्तर: क) Zero
Gauss's law states that the total electric flux through any closed surface is proportional to the enclosed charge. Since the point charge +q is at the center, it encloses no volume, and therefore the flux is zero. Option (b) incorrectly attempts to calculate the flux using a simplified formula without applying Gauss’s Law. Options (c) and (d) are incorrect as they involve calculations not based on the fundamental principles.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Plaster of Paris is used in hospitals for making casts to support fractured bones because, when mixed with water, it undergoes a rapid hydration reaction, forming a hard, porous material that provides initial support. This contrasts sharply with cement which sets much slower and is less suitable for this purpose. Which of the following statements accurately describes the chemical process involved?
सही उत्तर: क) It forms a strong covalent bond with calcium ions in bone tissue
Option 0 is correct. Plaster of Paris (CaSO₄·2H₂O) hydrates to form gypsum and water, a process that releases heat (exothermic). The other options describe incorrect reactions or properties.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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