चिकित्सा शिक्षा आयोग (CEE) पारामेडिकल (B.Pharm, BPH, BMLT, BMIT, B.Optom) तयारी
चिकित्सा शिक्षा आयोग (CEE) – पारामेडिकल (B.Pharm, BPH, BMLT, BMIT, B.Optom)
Paramedical Bachelor Entrance · Medical Education Commission – CEE
२,०३९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
MBBS/BDS/Nursing प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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An X-ray tube is operated at 25 kV. The minimum wavelength of the X-rays produced is about (hc = 12400 eV Å):
सही उत्तर: क) 0.5 Å
λ_min = hc/(eV) = 12400/25000 Å ≈ 0.5 Å.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A proton and an alpha particle have the same kinetic energy. The ratio of their de Broglie wavelengths λ_p : λ_α is:
सही उत्तर: ख) 2 : 1
λ = h/√(2mK) ∝ 1/√m; m_α = 4m_p, so λ_p/λ_α = √4 = 2, i.e. 2 : 1.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Light of wavelength 300 nm falls on a metal of work function 2.13 eV. The stopping potential is about (hc = 1240 eV nm):
सही उत्तर: ग) 2.0 V
Photon energy = 1240/300 ≈ 4.13 eV; K_max = 4.13 − 2.13 = 2.0 eV, so the stopping potential is about 2.0 V.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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At a place, the horizontal component of the Earth's magnetic field is 0.3 G and the angle of dip is 60°. The total intensity of the Earth's field there is:
सही उत्तर: घ) 0.6 G
H = B cos δ, so B = H/cos 60° = 0.3/0.5 = 0.6 G.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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If the number of turns of a long air-cored solenoid is doubled, keeping its length and area of cross-section the same, its self-inductance becomes:
सही उत्तर: क) four times
L = μ₀N²A/l ∝ N², so doubling N makes L four times.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A series LCR circuit with R = 30 Ω, X_L = 80 Ω and X_C = 40 Ω is connected to a 100 V (rms) AC supply. The rms current in the circuit is:
सही उत्तर: घ) 2 A
Z = √(R² + (X_L − X_C)²) = √(30² + 40²) = 50 Ω; I = V/Z = 100/50 = 2 A.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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An LC circuit has L = 10 mH and C = 1 μF. Its natural angular frequency of oscillation is:
सही उत्तर: ग) 10⁴ rad/s
ω₀ = 1/√(LC) = 1/√(10⁻² × 10⁻⁶) = 1/10⁻⁴ = 10⁴ rad/s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The magnetic flux through a coil varies with time as Φ = (5t² + 3t) Wb. The magnitude of the induced emf at t = 2 s is:
सही उत्तर: ख) 23 V
e = dΦ/dt = 10t + 3; at t = 2 s, e = 20 + 3 = 23 V.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A proton and an alpha particle, both starting from rest, are accelerated through the same potential difference and then enter a uniform magnetic field perpendicularly. The ratio of the radii r_p : r_α is:
सही उत्तर: ख) 1 : √2
r = √(2mV/q)/B ∝ √(m/q); m/q is 1 for the proton and 4/2 = 2 for the alpha particle, so r_p : r_α = 1 : √2.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A proton and an alpha particle enter the same uniform magnetic field perpendicular to it with the same speed. The ratio of the radii of their circular paths r_p : r_α is:
सही उत्तर: ख) 1 : 2
r = mv/(qB); for the alpha particle m is 4 times and q is 2 times that of the proton, so r_α = 2r_p and r_p : r_α = 1 : 2.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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