सर्भेक्षण – Surveying MCQ
सर्भेक्षण – सिभिल इन्जिनियरिङ
Surveying · Civil Engineering · १,५६५ प्रश्न
१,५६५ प्रश्न उपलब्ध। मोड छान्नुहोस्:
सर्भेक्षण: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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In an external-focusing tacheometer without an anallactic lens, the additive constant C is equal to:
सही उत्तर: घ) f + d, the focal length plus the distance from the objective to the vertical axis
The additive constant equals the focal length plus the distance between the objective and the instrument's vertical axis; an anallactic lens makes it zero.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In stadia tacheometry, the multiplying constant K of a tacheometer is equal to:
सही उत्तर: ख) f/i, where f is the focal length and i is the stadia hair interval
Similar triangles give D = (f/i)s + (f + d), so K = f/i and the additive constant C = f + d.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A traverse line running due east has:
सही उत्तर: घ) Zero latitude and departure equal to its length
Latitude = L cos 90° = 0 and departure = L sin 90° = L.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The coordinate differences between two stations are ΔN = 30 m and ΔE = 40 m. The distance between them is:
सही उत्तर: क) 50 m
Distance = √(30² + 40²) = √2500 = 50 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The coordinates of B relative to A are ΔN = −100 m and ΔE = +100 m. The whole circle bearing of AB is:
सही उत्तर: क) 135°
Latitude negative and departure positive means the line lies in the SE quadrant; reduced bearing S 45° E corresponds to WCB 135°.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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From station A (N 1000.00 m, E 1000.00 m), a line 100 m long has a whole circle bearing of 45°. The coordinates of B are:
सही उत्तर: ग) N 1070.71 m, E 1070.71 m
ΔN = 100 cos 45° = 70.71 m and ΔE = 100 sin 45° = 70.71 m, so B is (1070.71, 1070.71).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A closed traverse has a perimeter of 1000 m and a closing error in latitude of 0.5 m. Using Bowditch's rule, the correction to the latitude of a line 200 m long is:
सही उत्तर: ख) 0.1 m
Correction = error × (length of line/perimeter) = 0.5 × 200/1000 = 0.1 m (with sign opposite to the error).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In the 'fast needle' method of theodolite traversing:
सही उत्तर: ग) The magnetic bearing of the first line is observed and the bearings of other lines are obtained via the theodolite, with the needle clamped
In the fast needle method the needle is used only to orient the instrument at the start; bearings are then carried forward by angular measurement.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A theodolite main scale is divided into 20' divisions, and 40 vernier divisions equal 39 main scale divisions. The least count is:
सही उत्तर: ख) 30"
Least count = value of one main division ÷ number of vernier divisions = 20' ÷ 40 = 0.5' = 30".
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a theodolite, the index error of the vertical circle is eliminated by:
सही उत्तर: क) Taking the mean of face left and face right observations
Index error affects face left and face right readings equally and oppositely, so their mean is free of it.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
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