सिभिल इन्जिनियरिङ
सिभिल इन्जिनियरिङ
Civil Engineering · ५,१७१ प्रश्न
५,१७१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
सिभिल इन्जिनियरिङ: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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In the IS classification system, the group symbol 'CI' represents:
सही उत्तर: घ) Clay of intermediate plasticity (LL 35% to 50%)
IS divides fine soils by LL into L (below 35), I (35–50) and H (above 50); 'CI' is clay of intermediate plasticity.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In the IS soil classification, the particle size range of silt is:
सही उत्तर: क) 75 μm to 2 μm
Silt lies between 75 μm and 2 μm; particles finer than 2 μm are clay size.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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As per the IS classification of soils, the particle size boundary between gravel and sand is:
सही उत्तर: क) 4.75 mm
Gravel is coarser than 4.75 mm, sand is from 4.75 mm to 75 μm.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The toughness index of a soil is defined as the ratio of:
सही उत्तर: घ) Plasticity index to flow index
It = Ip/If, where If is the slope of the flow curve (water content vs log of number of blows).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In the cone penetration method (IS 2720 Part 5) for liquid limit, the liquid limit is the water content at which the standard cone penetrates:
सही उत्तर: घ) 20 mm
The liquid limit by the cone penetrometer is the water content corresponding to 20 mm penetration of the standard cone.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A soil has liquid limit 50%, plastic limit 25% and natural water content 30%. Its consistency index is:
सही उत्तर: ग) 0.8
Ic = (LL − w)/PI = (50 − 30)/25 = 0.8; a value near 1 indicates a stiff soil.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a pycnometer test: empty pycnometer 500 g, with dry soil 800 g, with soil and water filled 1500 g, with water only 1311 g. The specific gravity of soil solids is about:
सही उत्तर: ख) 2.70
G = (W2 − W1)/[(W2 − W1) − (W3 − W4)] = 300/(300 − 189) = 300/111 ≈ 2.70.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A soil has void ratio 0.8 and degree of saturation 60%. Its percentage air voids (na) is about:
सही उत्तर: क) 17.8%
n = e/(1 + e) = 0.444; air content ac = 1 − S = 0.4; na = n·ac = 0.444 × 0.4 ≈ 0.178, i.e. 17.8%.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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For a soil with G = 2.7 and e = 0.7 (γw = 10 kN/m³), the submerged (buoyant) unit weight is:
सही उत्तर: क) 10.0 kN/m³
γ' = (G − 1)γw/(1 + e) = 1.7 × 10/1.7 = 10.0 kN/m³ (equal to γsat − γw).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A soil has G = 2.7 and void ratio 0.7. Taking γw = 10 kN/m³, its saturated unit weight is:
सही उत्तर: घ) 20.0 kN/m³
γsat = (G + e)γw/(1 + e) = (2.7 + 0.7) × 10/1.7 = 20.0 kN/m³.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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