आधारभूत विद्युत् (Basic Electrical) – Basic Electrical Engineering MCQ
आधारभूत विद्युत् (Basic Electrical) – इलेक्ट्रिकल र टेलिकम
Basic Electrical Engineering · Technical – Electrical, Mechanical & Telecom · २,२९९ प्रश्न
२,२९९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
आधारभूत विद्युत् (Basic Electrical): प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A resistor and an inductor in series are connected to an AC supply. Which statement about Kirchhoff's voltage law is correct?
सही उत्तर: घ) KVL holds for instantaneous values and for phasors, but the RMS voltages across R and L do not add arithmetically to the supply voltage
v = v_R + v_L at every instant and V = V_R + V_L as phasors; because V_R and V_L are 90° apart, V = √(V_R² + V_L²), not V_R + V_L.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The substitution theorem states that a branch of a network carrying current I with voltage V across it:
सही उत्तर: क) can be replaced by an ideal source of that voltage V (or current I) without changing other branch currents and voltages
Replacing any branch by an independent source equal to its own voltage (or current) leaves all other conditions in the network unchanged.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Using the passive sign convention, an element has 10 V across it and a current of 2 A entering its negative terminal. The element:
सही उत्तर: ग) delivers 20 W (absorbed power is −20 W)
With current entering the negative terminal, p = −vi = −20 W absorbed, i.e. the element supplies 20 W (it acts as a source).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 12 V car battery with an internal resistance of 0.02 Ω supplies 200 A to the starter motor. The terminal voltage during cranking is:
सही उत्तर: क) 8 V
V = E − Ir = 12 − 200 × 0.02 = 12 − 4 = 8 V; this is why lamps dim while the engine is being cranked.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A battery drives 1 A through a 5 Ω resistor and 0.5 A through an 11 Ω resistor. Its emf and internal resistance are:
सही उत्तर: ग) 6 V and 1 Ω
E = 1 × (5 + r) = 0.5 × (11 + r) gives 5 + r = 5.5 + 0.5r, so r = 1 Ω and E = 6 V.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 12 V supply feeds two parallel branches: branch 1 is 2 Ω (top) in series with 4 Ω (bottom), and branch 2 is 4 Ω (top) in series with 2 Ω (bottom). The open-circuit voltage between the two midpoints is:
सही उत्तर: घ) 4 V
Measured from the bottom rail, midpoint 1 is at 12 × 4/6 = 8 V and midpoint 2 at 12 × 2/6 = 4 V, so the difference is 4 V.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 2 hp motor runs at full output for 4 hours. Taking 1 hp = 746 W and ignoring losses, the energy delivered is about:
सही उत्तर: ख) 5.97 kWh
P = 2 × 746 = 1492 W; energy = 1.492 kW × 4 h ≈ 5.97 kWh.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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One joule of electrical energy is equal to one:
सही उत्तर: ख) watt-second
Energy = power × time, so 1 J = 1 W × 1 s.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The colour rendering index (CRI) of a light source measures how faithfully it shows the colours of objects. Its maximum value, as for daylight or an incandescent lamp, is:
सही उत्तर: ग) 100
CRI is graded on a scale up to 100, the value assigned to the reference source; low-pressure sodium lamps have very poor CRI.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Compact fluorescent lamps (CFLs) need careful disposal mainly because they contain a small amount of:
सही उत्तर: घ) mercury
Fluorescent lamps work by a mercury-vapour discharge, so broken or discarded lamps release toxic mercury.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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