आधारभूत विद्युत् (Basic Electrical) – Basic Electrical Engineering MCQ
आधारभूत विद्युत् (Basic Electrical) – इलेक्ट्रिकल र टेलिकम
Basic Electrical Engineering · Technical – Electrical, Mechanical & Telecom · २,२९९ प्रश्न
२,२९९ प्रश्न उपलब्ध। मोड छान्नुहोस्:
आधारभूत विद्युत् (Basic Electrical): प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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Bundled conductors (two or more sub-conductors per phase) are used on EHV transmission lines mainly to:
सही उत्तर: क) reduce corona loss and line reactance
Bundling increases the effective conductor radius, lowering the surface electric stress (corona) and the inductance per km.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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An overhead conductor weighing 10 N per metre is strung between supports 200 m apart at the same level with a tension of 20 kN. The sag (S = wl²/8T) is:
सही उत्तर: क) 2.5 m
S = 10 × 200²/(8 × 20 000) = 400 000/160 000 = 2.5 m.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Utilities often penalise industrial consumers who operate at a low power factor because a low power factor:
सही उत्तर: ख) makes the utility supply more current (kVA) for the same kW, increasing losses and equipment size
For the same active power, current ∝ 1/cos φ, so poor power factor raises I²R losses and the kVA capacity needed.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A time-of-day (ToD) tariff encourages consumers to:
सही उत्तर: ग) shift their use away from peak hours by charging more for peak-time energy
Charging a higher rate in peak hours and a lower rate off-peak flattens the load curve and improves plant utilisation.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Under a block-rate tariff, the first 20 units cost Rs 4 each, the next 30 units Rs 7 each and further units Rs 9 each. The energy charge for 100 units is:
सही उत्तर: ख) Rs 740
20 × 4 + 30 × 7 + 50 × 9 = 80 + 210 + 450 = Rs 740.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 100 MW power station generates 438 GWh of energy in a year. Its plant capacity factor is:
सही उत्तर: घ) 0.5
Capacity factor = actual energy/(installed capacity × hours) = 438 000/(100 × 8760) = 0.5.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The diversity factor of a power system is normally:
सही उत्तर: ग) greater than 1
Individual maximum demands do not all occur at the same time, so their sum exceeds the system's maximum demand; hence diversity factor > 1.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Three consumers have individual maximum demands of 10 kW, 15 kW and 25 kW, while the maximum demand on the supply station is 40 kW. The diversity factor is:
सही उत्तर: क) 1.25
Diversity factor = sum of individual maximum demands/maximum demand of the system = 50/40 = 1.25.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A power station has a maximum demand of 50 MW and generates 219 GWh in a year (8760 h). Its annual load factor is:
सही उत्तर: घ) 0.5
Average load = 219 000 MWh/8760 h = 25 MW, so load factor = 25/50 = 0.5.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A consumer has a connected load of 10 kW and a maximum demand of 6 kW. The demand factor is:
सही उत्तर: घ) 0.6
Demand factor = maximum demand/connected load = 6/10 = 0.6.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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