प्राविधिक – इलेक्ट्रिकल, मेकानिकल र टेलिकम
प्राविधिक – इलेक्ट्रिकल, मेकानिकल र टेलिकम
Technical – Electrical, Mechanical & Telecom · ४,५०० प्रश्न
४,५०० प्रश्न उपलब्ध। मोड छान्नुहोस्:
इलेक्ट्रिकल र टेलिकम: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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A pure inductor connected to an AC supply:
सही उत्तर: क) stores energy during one quarter-cycle and returns it to the source in the next
Energy ½Li² builds up while |i| rises and is returned while |i| falls, so the net (average) power is zero.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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In a purely resistive AC circuit, the instantaneous power taken by the resistor:
सही उत्तर: ख) is never negative and pulsates at twice the supply frequency
p = vi with v and i always of the same sign, so p ≥ 0; p = VmIm sin²ωt varies at 2f.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A clamp meter is clamped around a two-core cable, enclosing both the live and the neutral conductor of a healthy single-phase load drawing 10 A. It reads about:
सही उत्तर: ख) 0 A
The equal and opposite currents in live and neutral produce cancelling magnetic fields, so the net current enclosed (and the reading) is zero; only one conductor should be clamped.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A resistor and an inductor in series are connected to an AC supply. Which statement about Kirchhoff's voltage law is correct?
सही उत्तर: घ) KVL holds for instantaneous values and for phasors, but the RMS voltages across R and L do not add arithmetically to the supply voltage
v = v_R + v_L at every instant and V = V_R + V_L as phasors; because V_R and V_L are 90° apart, V = √(V_R² + V_L²), not V_R + V_L.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The substitution theorem states that a branch of a network carrying current I with voltage V across it:
सही उत्तर: क) can be replaced by an ideal source of that voltage V (or current I) without changing other branch currents and voltages
Replacing any branch by an independent source equal to its own voltage (or current) leaves all other conditions in the network unchanged.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Using the passive sign convention, an element has 10 V across it and a current of 2 A entering its negative terminal. The element:
सही उत्तर: ग) delivers 20 W (absorbed power is −20 W)
With current entering the negative terminal, p = −vi = −20 W absorbed, i.e. the element supplies 20 W (it acts as a source).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 12 V car battery with an internal resistance of 0.02 Ω supplies 200 A to the starter motor. The terminal voltage during cranking is:
सही उत्तर: क) 8 V
V = E − Ir = 12 − 200 × 0.02 = 12 − 4 = 8 V; this is why lamps dim while the engine is being cranked.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A battery drives 1 A through a 5 Ω resistor and 0.5 A through an 11 Ω resistor. Its emf and internal resistance are:
सही उत्तर: ग) 6 V and 1 Ω
E = 1 × (5 + r) = 0.5 × (11 + r) gives 5 + r = 5.5 + 0.5r, so r = 1 Ω and E = 6 V.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 12 V supply feeds two parallel branches: branch 1 is 2 Ω (top) in series with 4 Ω (bottom), and branch 2 is 4 Ω (top) in series with 2 Ω (bottom). The open-circuit voltage between the two midpoints is:
सही उत्तर: घ) 4 V
Measured from the bottom rail, midpoint 1 is at 12 × 4/6 = 8 V and midpoint 2 at 12 × 2/6 = 4 V, so the difference is 4 V.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 2 hp motor runs at full output for 4 hours. Taking 1 hp = 746 W and ignoring losses, the energy delivered is about:
सही उत्तर: ख) 5.97 kWh
P = 2 × 746 = 1492 W; energy = 1.492 kW × 4 h ≈ 5.97 kWh.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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