आईओई इन्जिनियरिङ प्रवेश (त्रिवि) BE / B.Arch प्रवेश परीक्षा तयारी
आईओई इन्जिनियरिङ प्रवेश (त्रिवि) – BE / B.Arch प्रवेश परीक्षा
IOE BE / B.Arch Entrance · IOE Entrance (TU)
३,८४१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
BE/B.Arch प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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The work done by the centripetal force on a body moving in a uniform circular path is:
सही उत्तर: ग) Zero
Centripetal force is always perpendicular to the displacement, so W = Fs cos90° = 0. Hence the kinetic energy of the body stays constant.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The force that keeps a satellite moving in a circular orbit around the Earth is provided by:
सही उत्तर: ख) Gravitational attraction of the Earth
Earth's gravity provides the necessary centripetal force. Centrifugal force is only a pseudo force in the rotating frame, not a real force on the satellite.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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For a road banked at angle θ, the ideal speed v on a curve of radius r (no friction needed) satisfies:
सही उत्तर: क) tan θ = v²/(rg)
The horizontal component of the normal force supplies the centripetal force: N sinθ = mv²/r and N cosθ = mg, giving tanθ = v²/(rg).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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If θ is the angle of repose, the coefficient of static friction μ equals:
सही उत्तर: घ) tan θ
At the angle of repose, mg sinθ = μ mg cosθ, so μ = tanθ. This is also the angle of friction for the same surfaces.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A 10 kg block rests on a horizontal floor with coefficient of static friction 0.5. The minimum horizontal force needed to just move it is (g = 10 m/s²):
सही उत्तर: ग) 50 N
Limiting friction f = μmg = 0.5 × 10 × 10 = 50 N, so a force just exceeding 50 N starts motion. 100 N is the normal reaction, not the friction.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A person of mass 50 kg stands in a lift accelerating upward at 2 m/s². The reading of the weighing machine is (g = 10 m/s²):
सही उत्तर: ख) 600 N
N − mg = ma, so N = m(g + a) = 50 × 12 = 600 N. 400 N would be the reading if the lift accelerated downward.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A force of 20 N acts on a body of mass 5 kg. Its acceleration is:
सही उत्तर: क) 4 m/s²
a = F/m = 20/5 = 4 m/s². 100 comes from multiplying instead of dividing.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Newton's first law of motion gives the concept of:
सही उत्तर: घ) Inertia
The first law states a body remains at rest or uniform motion unless acted upon by an external force; this property is inertia. The second law gives a measure of force.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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At the highest point of a projectile's path (angle of projection between 0° and 90°), the velocity and acceleration are:
सही उत्तर: ग) Perpendicular to each other
At the top, velocity is purely horizontal (u cosθ) while acceleration g acts vertically downward, so they are perpendicular. Velocity is not zero there unless the throw is vertical.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Two trains move in opposite directions on parallel tracks at 54 km/h and 36 km/h. Their relative speed is:
सही उत्तर: ख) 25 m/s
For opposite directions speeds add: 90 km/h = 90 × 5/18 = 25 m/s. 5 m/s would be the relative speed if they moved in the same direction.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
AI ले गल्ती गर्न सक्छ। महत्वपूर्ण कुरा आधिकारिक स्रोतमा जाँच्नुहोस्।