आईओई इन्जिनियरिङ प्रवेश (त्रिवि) M.Sc. इन्जिनियरिङ प्रवेश तयारी
आईओई इन्जिनियरिङ प्रवेश (त्रिवि) – M.Sc. इन्जिनियरिङ प्रवेश
IOE M.Sc. Engineering Entrance · IOE Entrance (TU)
३,८४१ प्रश्न उपलब्ध। मोड छान्नुहोस्:
BE/B.Arch प्रवेश: प्रश्न र उत्तर
सही लागेको विकल्पमा थिच्नुहोस्। सही भए हरियो, गलत भए रातो देखिन्छ; ३ सेकेन्डपछि सही उत्तर र व्याख्या देखिन्छ।
सही: ० / ०
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In a U-tube containing water, oil is poured into one arm. A 10 cm column of oil balances an 8 cm column of water (measured from the interface level). The density of the oil is:
सही उत्तर: ख) 800 kg/m³
Equal pressures at the interface level: ρ_oil × 10 = 1000 × 8, so ρ_oil = 800 kg/m³.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The adiabatic bulk modulus of an ideal gas at pressure P (ratio of specific heats γ) is:
सही उत्तर: ख) γP
From PVᵞ = constant, dP/dV = −γP/V, so B = −V dP/dV = γP.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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The Young's modulus of a wire depends on:
सही उत्तर: ग) the material of the wire only
Young's modulus is a property of the material (at a given temperature); changing length, area or load changes stress and strain in the same ratio.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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When an additional 2 kg mass is attached to a mass hanging from a spring, the period of oscillation doubles. The original mass was:
सही उत्तर: क) 2/3 kg
T ∝ √m, so (m + 2)/m = 4, giving 3m = 2 and m = 2/3 kg.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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For SHM x = A sin(2πt/T), the displacement at t = T/8 is:
सही उत्तर: घ) A/√2
x = A sin(2π/8) = A sin 45° = A/√2.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A particle in SHM starts from an extreme position. The minimum time it takes to reach a displacement of half the amplitude (on the same side) is:
सही उत्तर: ख) T/6
x = A cos ωt; A/2 = A cos ωt gives ωt = π/3, so t = (π/3)/(2π/T) = T/6.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Neglecting the Earth's rotation, the minimum energy needed to put a satellite of mass m into a circular orbit at a height R above the Earth's surface (R = Earth's radius, g = surface value) is:
सही उत्तर: घ) 3mgR/4
Initial energy on the surface = −GMm/R; total energy in an orbit of radius 2R = −GMm/(4R). Energy needed = 3GMm/(4R) = 3mgR/4 (using GM = gR²).
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A satellite moves in a circular orbit close to the Earth. By what percentage must its speed be increased for it to escape from the Earth's gravity?
सही उत्तर: क) about 41.4%
Escape speed = √2 × orbital speed at the same distance, so the speed must increase by (√2 − 1) × 100% ≈ 41.4%.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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Two satellites of equal mass move in circular orbits of radii r and 2r around the Earth. The ratio of their kinetic energies is:
सही उत्तर: ग) 2 : 1
For a circular orbit KE = GMm/(2r), so KE ∝ 1/r and the ratio is 2r : r = 2 : 1.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
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A planet moves in an elliptical orbit around the Sun. Its distances from the Sun at perihelion and aphelion are r₁ and r₂. The ratio of its speeds there, v₁ : v₂, is:
सही उत्तर: क) r₂ : r₁
Angular momentum is conserved and at these points velocity is perpendicular to the radius: m v₁ r₁ = m v₂ r₂, so v₁ : v₂ = r₂ : r₁.
💬 टिप्पणी / गल्ती रिपोर्ट (०)
यी अभ्यास प्रश्न हुन्, आधिकारिक प्रश्न होइनन्। पाठ्यक्रम, विज्ञापन र नतिजाका लागि सम्बन्धित निकायको आधिकारिक वेबसाइट हेर्नुहोस्। उत्तरमा गल्ती भेटे प्रश्नमुनिको "टिप्पणी / गल्ती रिपोर्ट" मा लेख्नुहोस्।
नमस्ते! पाठ्यक्रम, सामान्य ज्ञान, भाषा परीक्षा वा कुनै प्रश्नको उत्तर बुझ्न सोध्नुहोस्।
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